You can answer this by the method of substitution, which means that you find what one variable equals and you substitute it into the second equation to find the other variable.
14x-2y=78; solve for y
-2y=78-14x; subtract 14x on both sides
y=-39+7x; divide both sides by -2
y=7x-39
Substitute 7x-39 for y in the second equation.
2x-2(7x-39)=6; solve for x
2x-14x+78=6; distribute the -2
-12x+78=6
-12x=-72; subtract 78 on both sides
x=6; divide both sides by -12
Now go back to the first equation and for x, substitute 6. You can either substitute in 14x-2y=78 or the y=7x-39, but it's easier where you already have y isolated.
y=7(6)-39
y=42-39
y=3
You got that x=6 and that y=3; therefore, the ordered pair is (6,3).
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
There are infinitely many ordered pairs. The coordinates of each of the infinite number of points on the straight line defined by 2x + 6y = 24 (or equivalently, 3y = -x + 12) is an ordered pair that satisfies the requirements.
( 8x2 - 14x - 30 ) divided by ( 2x - 6 ) = 4x + 5
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
k
The ordered pair is (1, 3).
14x - 14 = 2x + 46 14x - 2x = 46 + 14 12x = 60 x = 5
The ordered pair is (3, 2).
The ordered pair is (2, 3).
The ordered pair is (-1, -2).
There are an infinite number of ordered pairs. (-5, -7) is one pair
{-4,-5}
(10, 2)
(5,3)
x = -6 y = -11
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)