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+6 for each sulphur.

+1 for each Na; Two oxygens are as peroxides and will have -1 charge / oxidation number each. Six oxygens are as oxides and will have -2 charge each.

So, 2(+1) + 2y + 2(-1) + 6(-2) = 0

Or y = +6 (the charge / oxidation number of sulphur)

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11y ago
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Utkarsh Upadhyay

Lvl 2
2y ago

+1 for each Na; Two oxygens are as peroxides and will have -1 charge / oxidation number each. Six oxygens are as oxides and will have -2 charge each.

So, 2(+1) + 2y + 2(-1) + 6(-2) = 0

Or y = +6 (the charge / oxidation number of sulphur)

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Utkarsh Upadhyay

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2y ago
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12y ago

It contains two sulfur atoms. One(in the center) has +6 oxidation state, while the other has -2 oxidation state.

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Anonymous

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3y ago

+6

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Anonymous

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3y ago

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Q: What is the oxidation number of sulfur in Na2S2O8?
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