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The oxidation state of Sb in Sb2O4 is +4. As the oxygen has the oxidation state equal to -2, we have four oxygen atoms in total, so the negative charge is equal to -8. now to balance it we should have +8 charge as Sb2O4 is neutral. but we have two Sb atoms per molecule.so the each Sb atom has the charge equal to +4.

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12y ago
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9y ago

Difficult one- H is +1 generally except with recative metals wheen it is -1. Sb is not reactived so Sb has ox number of -4. HOWEVER SbH4 does not exist, I think you mean SbH3 where Sb would have ox # of -3

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12y ago

-3, 0, 3 and 5 oxidation states

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13y ago

-3,+3, or +5

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Q: What is the oxidation number of Sb in SbH4?
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