The oxidation state of Sb in Sb2O4 is +4. As the oxygen has the oxidation state equal to -2, we have four oxygen atoms in total, so the negative charge is equal to -8. now to balance it we should have +8 charge as Sb2O4 is neutral. but we have two Sb atoms per molecule.so the each Sb atom has the charge equal to +4.
Difficult one- H is +1 generally except with recative metals wheen it is -1. Sb is not reactived so Sb has ox number of -4. HOWEVER SbH4 does not exist, I think you mean SbH3 where Sb would have ox # of -3
-3, 0, 3 and 5 oxidation states
-3,+3, or +5
The oxidation number of Sb in Sb2O5 is +5.
In Sb2O5 the oxidation number for Sb is +5 and O is -2
oxygen is 2- so four oxygen have 8- charges therefore two Sb should have 8+ and therefore the oxidation number of Sb is 4+
oxidation number of I is -1. oxidation number of F is +1.
The Atomic Number is 51 and the mass is 121.76.
The oxidation number of Sb in Sb2O5 is +5.
In Sb2O5 the oxidation number for Sb is +5 and O is -2
oxygen is 2- so four oxygen have 8- charges therefore two Sb should have 8+ and therefore the oxidation number of Sb is 4+
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Sb (antimony) oxidation states +3, +5, to oxygen -2: (it behaves like phosphor) 4Sb + 3O2 --> 2Sb2O3 4Sb + 5O2 --> 2Sb2O5
The Atomic Number is 51 and the mass is 121.76.
Zn has oxidation number +2; S has oxidation number -2
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Oxidation number of Si is +4.Oxidation number of O is -2.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.