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The oxidation number for BaSO4 is 6. It goes as follows:

+2 for Ba

+6 for S

-2 for O

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Wiki User

9y ago
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Wiki User

16y ago

it is +3 and O2 is -2 so when combining something like S8 + O2 you ger sulfur dioxide (SOz) but when balanced it is S2O3

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Wiki User

9y ago

The oxidation number in Sulfur in BaSO4 is S=6.

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Wiki User

11y ago

It should be S4O62- ion -2 for each O. Two of the sulfur atoms present in the ion are in oxidation state 0 and two are in oxidation state +5.

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Wiki User

9y ago

The oxidation state of a sulfur atom in BaSO4 is +6.

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Wiki User

11y ago

+4 for sulfur

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Raj Patel

Lvl 1
1y ago
+4= x+(-2*2)

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Wiki User

12y ago

outer is -2, inner is +6.

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Harshika Jain

Lvl 2
1y ago

2 + x + (4 * -2) = + 6

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Wiki User

12y ago

+5/2

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Q: What is the oxidation number for BaSO4?
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