Hi,
CrO5 is a compound which has the structure which has peroxide linkage(O2 2-) as shown:
Thus the oxidation number of Chromium can be calculated as :
Let the oxidation number of Cr be x, then
x-2-2(2)=0
x-2-4=0
x-6=0
thus x=+6
The valence of chromium is 2 in CrO.
+2
The overall oxidation state of a compound equals 0. The oxidation state of oxygen is -2. So the oxidation state of the chromium is +2. (+2 + (-2) = 0
oxidation state of Cr is +4.
what is the oxidation state of Cr in CrO
+6 oxidation state
+3 oxidation state
Green in its II and III oxidation states and orange in its VI oxidation state.
Balance the oxidation states on the atoms in the molecule. An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-. As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get CrO2 (which you can write as Cr4+ (O2-)2 )
Chromium is a metal and, like most metals, it's a sort of shiny gray color ("silvery"). Chromium compounds can be most any color: red, orange, yellow, green, blue, and violet chromium compounds are all known. The color depends on the oxidation state of the chromium and also on what ligands are present (particularly in chromium (III) compounds).
+6 oxidation state
+3 oxidation state
CrO is the formula for chromium(II) oxide. Cr is the elemental symbol for chrome, and O represents oxygen. The molecular weight of CrO is 68.00 grams/per mole using two significant figures. Variants of CrO include II, III and VI.
Green in its II and III oxidation states and orange in its VI oxidation state.
chromium monoxide
Oxidation state of: Chromium = +6 Oxygen = -2 Hydrogen = +1
Chromium(II) oxide.
Chromium has four oxidation states: 2, 3, 4, and 6.Iodine has one, and it's -1.There will be a iodide for each oxidation state of chromium.CrI2 Chromium (II) iodideCrI3 Chromium (III) iodideCrI4 Chromium (IV) iodideCrI6 Chromium (VI) iodide
Assuming the 3 oxidation state of chromium.CrCl3====
it is a chromium 2 as a good point of reference, and if you don't know the specific charge of an atom, check the ion to which it is bound: the phosphide ion is most commonly charged as a 3- ion because its period is has 3 electrons more than it needs to form a complete octet 2 phosphide ions (per your empirical formula) would have a total ionic charge of 6- if you distribute the (6-) charge evenly through the 3 chromium ions in your empirical formula, then each chromium ion would have to have a charge of 2+ in order for the ionic salt to be neutrally charged. therefore the chromium is chromium (II)
The dichromate ion is Cr2O72- and the chromium is in oxidation state 6. When it acts as an oxidizing agent it usually reduces from 6 to 3.2Cr2O72- -----> 4Cr3+ + 7O2 + 16e-See the related link for more information.
Balance the oxidation states on the atoms in the molecule. An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-. As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get CrO2 (which you can write as Cr4+ (O2-)2 )