Oxidation State is -1.
This is because N= 5 AND O=-2
5+3*(-2)=-1
The Oxidation state of NO3=-1 This is because N=5 and O=-2 therefore 5+(3*-2)=-1
+5 oxidation state
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
because the oxidation state of N decreases
Platinum is connected to two anionic Chloride ligands and two neutral Ammine ligands Platinum = +2 oxidation state Chlorine = -1 oxidation state Nitrogen = -3 oxidation state Hydrogen = +1 oxidation state
Nitrogen, Phosphorus, Vanadium, etc.
If you are referring to the nitrate ion, NO3-, the oxidation number of oxygen would be O2- and nitrogen would be N5+. If you are talking about nitrogen trioxide NO3, the oxidation number of oxygen would be O2- and nitrogen would be N6+. Edit: Nitrogen trioxide does not exist in its free state.
Copper: 2+Oxygen: 2-Nitrogen: 5+
-2 for each oxygen and +5 for nitrogen in NO3- ion
Phosphorus in PCl5 Nitrogen in Nitrate (NO3-) ion
The oxidation number of nitrogen in the nitrate ion NO3- is 5
Nitrogen is in the 3- oxidation state in calcium nitride.
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
+5 oxidation state
In Ag NO3 the oxidation number of Ag (Silver) is 1+, the oxidation number of N (Nitrogen) is 5+, and the oxidation number of O (Oxygen) is 2-.
because the oxidation state of N decreases
The Oxidation number is an apparent charge on a single atom in an ion or molecule in Nitrate the Oxidation number of Nitrogen is +5 and -6 for three oxygen atoms (-2 each) so net charge on Nitrate ion is -1.
The crisscross method uses the oxidation state (valence) of each element or ion. In this example, aluminum (Al) has an oxidation number of 3+. Nitrogen has an oxidation number of 3-. So, there really is no crisscross, because they are both the same, and they would combine to make aluminum nitride, AlN. If, however, you had aluminum, and nitrate ion (NO3^-), the crisscross would be to make the Al subscript a 1 and the NO3- subscript 3 to give Al(NO3)3.