- log(1 X 10^-5 M) = 5 14 - 5 = 9 pH ----------
No, pH 2.77 is not the correct pH for 1 M HCl. The pH of 1 M HCl should be 0 (zero) because pH is the negative log the the H+ and for 1 M HCl the [H+] is 1 M, and the negative log of 1 is 0.
pH = -log [H+], so if the [H+] is 2.310 M, the pH = -0.3636
pH=-log[H+] pH-log(1.2x10^-3) pH=2.92 since the the pH plus the pOH is always equal 14 14-2.92=11.08 so the pOH is 11.08
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
No, CsOH (cesium hydroxide) is a strong base because it dissociates completely in water to produce Cs+ ions and OH- ions. This makes it highly effective at accepting protons, leading to a high pH in aqueous solutions.
Yes. One of the guidelines, per my general chemistry textbook, for determining if bases are strong is as follows:M2O or MOH where M is a Group 1A metal (Li, Na, K Rb, Cs) orMO or M(OH)2 where M is a Group 2A metal (Ca, Sr, Ba)CsOH fits the pattern for the first guideline, and so is a strong base and dissociates almost completely in water.
CsOH is considered a strong base because it dissociates completely in water to form Cs+ and OH- ions. This results in a high concentration of hydroxide ions in solution, making it an effective base for neutralizing acids.
3. since the [H+]=0.001 M then pH= -log[H+] -log(0.001)=3 pH=3.
its PH is 3
CsOH is a chemical compound called Caesium Hydroxide.
Britton-Robinson buffer is a "universal" pH buffer used for the range pH 2 to pH 12. Universal buffers consist of mixtures of acids of diminishing strength (increasing pKa) so that the change in pH is approximately proportional to the amount of alkali added. It consists of a mixture of 0.04 M H3BO3, 0.04 M H3PO4 and 0.04 M CH3COOH that has been titrated to the desired pH with 0.2 M NaOH. Britten and Robinson also proposed a second formulation that gave an essentially linear pH response to added alkali from pH 2.5 to pH 9.2 (and buffers to pH 12). This mixture consists of 0.0286 M citric acid, 0.0286 M KH2PO4, 0.0286 M H3BO3, 0.0286 M veronal and 0.0286 M HCl titrated with 0.2 M NaOH.
The pH of a 0.1 M solution of HBr (hydrobromic acid) is around 1. It is a strong acid that dissociates completely in water to produce H+ ions, resulting in a low pH.
if 0.000001 is the hydrogen ion concentration the pH is 6
The pH of a solution containing 0.1 M of HC2H3O2 is around 2.88.
- log(1 X 10^-5 M) = 5 14 - 5 = 9 pH ----------
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)