1.7
pH: -log(0.0250) = 1.6
pOH:
14-pH=pOH
14-1.6=pOH
12.4 M =pOH
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
1.7321856455215488
The pOH is 10,44.
12.3979
The pOH is 6,4.
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
12.85
pH + pOH = 14. So pOH = 14 - 10.95 = 3.05 pOH = -log[OH-] [OH-] = 8.91 x 10-4 M
pH + pOH = 14pH = -log 3.60x10^-10 = 9.44pOH = 14 - 9.44 = 4.56
1.70
12.85 is the pOH.
1.70
[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48
1.70
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
The pOH is 6,4.
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
12.85
12.85
1.70
1.70