What is the percent by mass of oxygen in NO2?

Answer 1

first we work out the Mr.

Mr= 80g

Then we find out the Mr of Oxygen in NH4NO3.

Mr of oxygen=48g

Then we do 40/80 which equals 0.5 then we multiply it by 100 and we get 50%

This is our Percentage by mass.

Answer 2

The formula given shows that each formula unit contain two nitrogen atoms (one in the ammonium ion and one in the nitrate ion). The gram formula mass of ammonium nitrate is 80.04 and the gram Atomic Mass of nitrogen is 14.0067. Therefore, the percent by mass of nitrogen in ammonium nitrate is:

100[(2)(14.0067)/80.04] or 35.00 %, to the justified number of significant digits. (A more precise gram formula mass of ammonium nitrate would justify more significant digits.)

Answer 3

1. Determine the molar mass of NH4NO3 by determining the molar mass of each element in the formula and then adding them together.

N: 2 x 14.534g/mol = 29.068g/mol

H: 4 x 1.008g/mol = 4.032g/mol

O: 3 x 15.999g/mol = 47.997g/mol

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Molar mass of NH4NO3 = 81.097g/mol

2. Divide the molar mass of each element by the molar mass of NH4NO3 and multiply the result times 100. This gives you the percent composition of each element in the compound.

N: (29.068g/mol)/(81.097g/mol) x 100 = 35.843%

H: (4.032g/mol)/(81.097) x 100 = 4.971%

O: (47.997g/mol)/(81.097g/mol) x 100 = 59.188%

Answer 4

N: 1(14)= 14

O: 2(16)= 32

14+32= 46

32/24x100= 70%

Answer 5

NH4NO3

N - 14.0 X 2 = 28

H4 - 1.0 X 4 = 4

O3 - 16.0 X 3 = 48

Total molecular mass = 80

48/80 = 60%

Answer 6

Sodium bicarbonate contain 57,137 % oxygen.

Answer 7

The percentage by mass of sodium (Na) in a formula unit of sodium hydrogen carbonate (NaHCO3) is 27,38 %.

Answer 8

The percent by mass of oxygen in N2O4 is 69,56 %.

Answer 9

28 g N/80 g NH4NO3 *100

Answer 10

ammonium nitrate contains 35% nitrogen.