the discount
No. For example, 500 increased by 10% = 550 Now, decreasing 550 by 10% results in: 495, not 500.
Total revenue increases to [ (original) x (1.45) x (1.53) ] = original x 2.2185 = 121.85% increase
Multiply the original figure by 1.45 !
Any percent less than 100.
in equilibrium
No. For example, 500 increased by 10% = 550 Now, decreasing 550 by 10% results in: 495, not 500.
Total revenue increases to [ (original) x (1.45) x (1.53) ] = original x 2.2185 = 121.85% increase
As you increase the concentration of the solution, the concentration of H+ does not change. Meaning, the concentration ionized does not change. Just the original concentration increases. Since percent ionization = (concentration ionized)/(original concentration) , and the original concentration is increased, the percent ionization therefore decreases.
increases by 10 percent increases by 10 percent increases by 10 percent
change of any quantity divided by its original quantity
percent of decrease
40*1.4 = 56
Since the original value of 50 decreases to 18, it has a % decrease and not a percent increase. % decrease = [(50 - 18)/50] x 100% = 64%
A percent of decrease (percentage decrease) is when a value is reduced by a percentage of its original amount. e.g. 100 decreased by 15 percent is 85. A percent of increase (percentage increase) is when a value in increased by a percentage of its original amount. e.g. 100 increased by 15 percent is 115.
25 percent
25 percent
55 to 60 is an increase of 9.09%