What is percent composition for sulfur in H2SO4?

Answer 1

Sulfuric acid - H2SO4

Find the atomic masses of all the elements and multiply each mass by the number of atoms in the compound, then add.

H: 1.00 × 2 = 2.00

S: 32.1

O: 16.0 × 4 = 64.0

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2.00 + 32.1 + 64.0 = 98.1 grams

Take the masses of each element and divide it by the total mass. Change the final answer to a percent.

H: 2.00 ÷ 98.1= 0.020 = 2.0%

S: 32.1 ÷ 98.1= 0.327 = 32.7%

O: 64.0 ÷ 98.1= 0.652 = 65.2%

There is 2.0% of hydrogen, 32.7% of sulfur, and 65.2% of oxygen in Sulfuric acid.

Answer 2

I think this is it but I may be wrong,

Add up the Atomic masses

H: 2 x 1 = 2

S: 1 x 32 = 32

O : 4 x 16 = 64

Added them all up = 98

Then percentage:

H: 2/98 x 100 = 2.04...%

S: 32/98 x 100 = 32.65...%

O: 64/98 x 100 = 65.31...%

Hope I helped

Answer 3

The formula given in the question shows that each formula unit contains two hydrogen atoms, one sulfur atom, and four oxygen atoms. The gram atomic masses for hydrogen, sulfur, and oxygen are 1.00794, 32.06, and 15.9994 respectively. Therefore, the mass percent composition of sulfur in H2SO4 is:

100{32.06/[32.06 + (2)(1.000794) + (4)(15.9994)]} or 32.70 %,

to the justified number of significant digits. The atomic percent of sulfur is 100(1/7) or about 14.2857143; more significant digits are justified for this result, because the integers 100, 1, 2, and 4 are all exact.

Answer 4

Sulfur: 94,069 48 %

Hydrogen: 5,930 52%

Answer 5

Approximately 50%. S is 32 and 2 O's are also 32. 32/64 = 0.5

Answer 6

Sulfur dioxide contain 49,986 % sulfur.

Answer 7

Concentrated sulfuric acid has 98 % H2SO4.

Answer 8

The percentage composition for SO2 is: sulfur - 50 % and oxygen - 50 %.