0
What is the percent by weight of a solution prepared by dissolving 10 g of NaCl in 100 g of H2O?
Wiki User
∙ 7y ago
% by weight in solution =
= 100 * (weight solute) / [(weight solvent) + (weight solute)]
= 100 * (weight solute) / [weight solution]
= 100* 10 / [100 + 10]
= 100 * 10 / 110
= 9.1%
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoThis solution is 100(2.19/75) = 2.9 percent sodium chloride, to the justified number of significant digits.
Wiki User
∙ 7y agoTotal mass = 10 g + 100 g = 110 g
% NaCl by wt = 10 g/110 g (x100) = 90.1%
Wiki User
∙ 6y agoThe percentage concentration is 12 %.
Add your answer:
Earn +20 pts
Why dont you weigh a solution dispensed at the beginning of an experiment?
Technically, as long as you record the volume of the solution and are sure of the concentration, you could extrapolate the weight.
How do you convert 100 gallons of 32 percent UAN to 28 percent UAN?
32% has a density of 11.04#/gal so 100 gal=1104#. 1104#*32%=353.28# of Nitrogen To convert 353.28# of Nitrogen into a 28% solution instead of 32% you must divide the #of nitrogen by the new solution value to get total pounds of new soultion and the ability to subtraced the two values to determine the total dilutant needed: 353.28#N in 28% solution would be 353.28/28%=1261.71# 28% solution 1261.71# 28% -1104# 32%= 157.71# of dilutant (water) needed to make 28% soultion. To figure out what percentace 32% is of the solution you divide the 32% solution weight by the new soultion weight: 1104/1261.71=.875 28% therefore is 87.5% of 32% by weight not volume. To solve the problem you need to divide the original weight of 32% by its percentage in the new solution to get the total solution weight of the new solution and then subtract the original solution weight to get the amount of dilutant needed to dilute 32% to a 28% solution. Do the following: (1104/.875)-1104=1261.71# of 28% solution. To dilulte 100 gal of 32% you will need to add water to get to the final weight of 28% solution 1261.71# 28%-1104# 32%=157.71# Dilutant (18.91 gal) Finished product you will have 118.91gal of 28% weighing 1261.71# 28% solution will be 10.611#/gal The fomula for this problem would be ((Galons 32% * 11.04)/.875)-(gal 32% * 11.04)= dilutant need. (gal 32% * 11.04)+ dilutant = # of 28% solution.
What is 6 to 8 percent of total body weight for an adult human?
do u really think i kno
How much does 1 body fat weigh?
Again, it is essential to know more then the question provides data on. Women need between 12 an 15 percent Essential body fat. Female athlletes carry about 18 percent bodyfat, healthy women carry about 26 percent, and an obese woman has 32 percent of more body fat. Men are considered obese at 25 percent Male athletes carry about 10 percent body fat and the survival level or Essential for men is at least two percent. When bodyfat falls below Essential levels the body's organs begin shutting down.
An object floats because it displaces a weight of fluid?
An object floats for three reasons. One, it is less dense than the solution it is floating in. Such as a piece of wood. Two, the object contains something that is less dense than what it is floating in. Such as a baloon. Three, the shape of the object is such that it does not have enough weight to displace enough of the solution to envelop the object. Such as with any seagoing vessell.
What is the weight percent of a caffeine solution made by dissolving 8.35 g of caffeine C8H10N4O2 in 75 g of benzene C6H6?
3g
How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
What is the concentration of FeCl3 in a solution prepared by dissolving 40.0 g of FeCl3 in enough water to make 275 mL of solution?
Look up or calculate the molecular weight/molar mass of FeCl3. Then... 40.0 g FeCl3/MW FeCl3/0.275 L = M (concentration of FeCl3 in solution)
What is the percentage concentration of a solution prepared by dissolving 5.48 grams of silver nitrate in 25.0 grams of water?
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
What does 5wt mean in oil weights?
This is the number of grams of solute in 100 grams of solution. As an example, a 5%w/w solution in water is prepared by dissolving 5 grams of solute in water and then adding further water with mixing until the final weight is 100 gram.
How many grams in 1 percent solution?
A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.
What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of solution?
Iron (III) chloride has the molecular formula of FeCl3. Its molecular weight is 162.2 grams per mole. Concentration is moles of solute divided by volume of solution. Therefore, the answer is .224 moles per liter.
How do make a percent sucrose solution?
Calculate the weight of sucrose for the desired volume and concentration of the solution.
What is meant by 47 percent of NaOH solution?
This term means that 47% of the weight of this solution is sodium hydroxide.
What is the molality of 7.80 percent by weight glucose solution?
Assuming that is is a solution of glucose in water, the answer is 93%.
If you have a 300ml of a 15 percent hydrochloric acid solution in dilute the solution to 1000ml with sterile water what percent should appear on the label?
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
