Suppose that a pendulum has a period of 1.5 seconds. How long does it take to make a complete back and forth vibration? Is this 1.5 second period pendulum longer or shorter in length than a 1 second period pendulum?
Such a device has actually been constructed. Its motion is found to require 0.5 second back
followed by 0.5 second forth, for a total period of one second.
Well, T = 2PIE x Sqroot (L/g)
so if T = 1, then just divide by 2PIE and Square it, then multiply by g. g is gravity
The answer is cleverly embedded in the question. If it takes one second to make a complete vibration, then that's the period.
The time that it "takes" is the period.
1/3 second is
2 Seconds
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
The answer is cleverly embedded in the question. If it takes one second to make a complete vibration, then that's the period.
Second's pendulum is the one which has 2 second as its Time period.
its the time taken for one complete vibration.
The time that it "takes" is the period.
The period is 1 second.
1/3 second is
2 Seconds
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
"Period" has the dimensions of time. Suitable units are the second, the minute, the hour, the fortnight, etc.
That depends on the period of the clock's pendulum. If we assume it's one second, then it does 1800 cycles in half an hour.
1/4 Hertz or 1.4 per second.
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2