If you are talking about the toss of a coin, the probability for a head coming up on the fourth toss is identical to the probability of a head coming up on the first toss, or the 17th or the 9,437th: Exactly 50/50.
Assuming a two-sided coin, and that you make the the toss, the probability of tossing a head or a tail is 100%. The probability of tossing a head is 50%. The probability of tossing a tail is 50%.
The probability of Tails on the first toss is 0.5 .The probability of Tails on the second toss is 0.5 .The probability of Tails on the third toss is 0.5 .The probability of Tails on the fourth toss is 0.5 .The probability of all four is (0.5 x 0.5 x 0.5 x 0.5) = 0.0625 = 6.25%
total outcome in single toss={H,T} u want 1 head probability of getting 1 head= 1/2=0.5
1/2. What the previous tosses are has no impact on what a fourth toss of a coin is, so the chance of getting a tails is the same on any throw.
you toss 3 coins what is the probability that you get exactly 2 heads given that you get at least one head?
The probability of Tails on the first toss is 1/2.The probability of Tails on the second toss is 1/2.The probability of Tails on the third toss is 1/2.The probability of Tails on the fourth toss is 1/2.The probability of Tails on the fifth toss is 1/2.The probability of Tails on the sixth toss is 1/2.The probability of Tails on the seventh toss is 1/2.The probability of all of them is (0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5) = (0.5)7 = 0.0078125= 0.78125 %
you have one twelfth chance
one out of four
If it is a fair coin, the probability is exactly 50%. The coin has no memory of what it did in the last flip. ■
Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%
If you toss them enough times, the probability is 1. For just one toss the probability is 1/4.
50%