Assuming the coin is fair, it is (1/2)5 = 1/32.
It is 3/1024 = 0.00293, approx.
The probability of flipping a coin 3 times and getting 3 heads is 1/2
None, since that would imply that in 18 cases the coin did not show heads or tails!
The probability of flipping one coin and getting tails is 1/2. In order to find the probability of multiple events occurring, you find the product of all the events. For 3 coins the probability of getting tails 3 times is 1/8 because .5 x .5 x .5 = .125 or 1/8.
Theoretical is 50% Heads, 50% tails: 30-Heads, 30-Tails (theoretical)
Every time you flip a coin it has a 50% chance of heads and a 50% chance of tails. Flipping a coin multiple times does not change that. Therefore the answer is 50%
1/2 of a chance since there are two sides to any coins it is always a half chance.
Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %
Since each event is independent, the probability remains at 0.5.
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
P(tail) is 0.5. You want P(tail) AND P(tail) = 0.5 * 0.5 = 0.25 or 1/4.
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The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%
1:6 * * * * * No. It is 10/32 = 5/16
The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .
The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)
There are 8 permutations of flipping a coin 3 times, or of flipping 3 coins one time. They are, with the permutations of two heads bolded...TTTTTHTHTTHHHTTHTHHHTHHH... thus, the probability of flipping a coin 3 times and getting 2 heads is 3 in 8, or 0.375.
The probability is 3/8.The probability is 3/8.The probability is 3/8.The probability is 3/8.
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25
The probability of each coin flip, independently, is 0.5 or 50%. The probability of getting one result (either heads or tails) four times in a row is 0.5 to the fourth power or 0.0625, which equals 6.25%
That depends how many times you flip the coin.
You still still have a 1:2 chance of getting heads regardless of the times you flip.
The answer I'm editing says the odds are 1 in 8. This is true only if you actually mean the probability of getting 3 tails in a row, rather than just 3 of either heads or tails in a row. In mentioned case, the first flip doesn't matter which side it lands on, just the proceeding two flips do. So, the odds of flipping a coin three times with the same outcome are 1 in 2^2 or 1 in 4. The odds of flipping three tails in a row are 1 in 2^3 or 1 in 8.