The probability of getting at least 1 tails is (1 - probability of getting all heads)
The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
One hundred percent it you toss the coin eight times.
Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.
the answer is 2/13
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
The probability is 61.538 if you are starting with a fresh deck and it is the first draw.
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
One in eight, or 12.5%.
Looking at the total possibilities, you have eight different outcomes: TTT TTH THH HHH HHT HTT HTH THT Counting your two heads, one tails, you get a total of 3 possibilities out of 8, or 3/7
It is 93/256 = 0.363 approx.
The experiment is undefined. On a single roll of eight or more normal dice the probability of getting a sum of 7 is 0.
The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.
The probability is (4/52) * (4/52) = 1/169 = 0.0059, approx.
The probability of flipping a heads is 1/2 and the probability of rolling a 6 is 1/6. By the laws of probability it would be logical to multiply them together, (1/2)(1/6) thus the answer being 1/12 with is roughly eight percent.
If you're including jokers, 4/52-if you're not including jokers-4/50 (8%).
The 8 coins are: 3 quarters, 2 dimes, 1 nickel and 2 pennies.
The probability of getting at least 1 answer correct = 1 - Probability of getting all answers correct.So in your case it for be P(at least 1 answer correct) = 1 - 1/256where 256 is your sample space, |S| = 2^8.
This is a problem concerning binomial probability distribution. If you have three coins, each one can land heads or tails. (We will ignore the remote chance that a coin will land on its edge.) Each coin has an equal probability of landing heads or tails. In other words, each coin has two possible states. Since there are three coins, there are 2 x 3 = 6 possible states. We can easily see what they are with a table: HHH HHT HTH HTT THH THT TTH TTT Three of those possible eight states contain two and only two heads. So the probability of throwing any of those three states is three in eight, or 3/8 = 0.375.
It you mean two 8 in a row then it's (1/8)2 = 1/64 as the probability to get 8 is 1/8
If you toss eight coins, there are 256 (28) different outcomes.
(8!/(6!2!) / 2**8 = 28/256 = 7/64 = 0.109375
Assuming the numbers are 1-6, the probability is 0.
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
Probability of not 8 heads = 1- Prob of 8 heads. Prob of 8 heads = 0.5^8 = 0.003906 Prob of not 8 heads= 1- 0.003906 = 0.99604