Probability

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The probability of getting all heads if you flip a coin three times is:

P(HHH) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8.

The probability of getting all tails if you flip a coin three times is:

P(TTT) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8.

The probability of getting all heads or all tails if you flip a coin three times is:

P(HHH or TTT) = P(HHH) + P(TTT) = 2/8 = 1/4.

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0There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.

Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %

In three tosses, the probability is 3/8.

The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.

The probability to get heads once is 1/2 as the coin is fair The probability to get heads twice is 1/2x1/2 The probability to get heads three times is 1/2x1/2x1/2 The probability to get tails once is 1/2 The probability to get tails 5 times is (1/2)5 So the probability to get 3 heads when the coin is tossed 8 times is (1/2)3(1/2)5=(1/2)8 = 1/256 If you read carefully you'll understand that 3 heads and 5 tails has the same probability than any other outcome = 1/256 As the coin is fair, each side has the same probability to appear So the probability to get 3 heads and 5 tails is the same as getting for instance 8 heads or 8 tails or 1 tails and 7 heads, and so on

Because you are thinking permutations rather than combinations. There are four permutations of two coins, but there are only three combinations, because it does not matter which coin is heads and which coin is tails. As a result, the combination of heads and tails has a 0.5 probability, while two heads or two tails each have a 0.25 probability.

Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.

The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .

The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.

What is the chance of it landing on heads twice in a row?

1heads heads heads 2heads heads tails 3heads tails heads 4heads tails tails 5tails tails tails 6tails tails heads 7tails heads tails 8tails heads heads

If you toss a coin often enough, it is a certainty, so that the probability = 1. The probability of that outcome in the first five tosses of a coin is (1/2)5 = 1/32.

The probability of flipping one coin and getting tails is 1/2. In order to find the probability of multiple events occurring, you find the product of all the events. For 3 coins the probability of getting tails 3 times is 1/8 because .5 x .5 x .5 = .125 or 1/8.

The probability of the coin coming up heads each time is 1/8; likewise for 3 tails. The probability of getting 2 heads and 1 tail (in any order) or 2 tails and 1 head, is 3/8. There are lots of other events whose probability can be calculated when a coin is tossed 3 times, but the question doesn't specify what event is to have its probability calculated.

Each toss has a 1/2 probability of getting heads. Each toss is an independent event. So three heads in a row (heads AND heads AND heads) would have a probability of:1/2 * 1/2 * 1/2 = (1/2)^3 = 1/(2^3) = 1/8 = 12.5%

3/8, or 37.5%There are eight possible sequences that can emerge from three coin tosses. Three have heads twice and tails once. Three have the opposite, two tails and one heads. The remaining possibilities are all heads or all tails.H H TH T HT H HT T HT H TH T TH H HT T T

well it depends on what you are tossing, if its a coin then no. it can be heads too. it would have to be a great coincidence for it to be all tails, but thats why the word probability comes in meaning that there is more than one outcome

For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times

the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.

The probability of flipping three tails with three coins is (1 in 2)3 or 1 in 8 or 0.125.

three heads two head, one tails one heads, two tails three tails

This is a problem concerning binomial probability distribution. If you have three coins, each one can land heads or tails. (We will ignore the remote chance that a coin will land on its edge.) Each coin has an equal probability of landing heads or tails. In other words, each coin has two possible states. Since there are three coins, there are 2 x 3 = 6 possible states. We can easily see what they are with a table: HHH HHT HTH HTT THH THT TTH TTT Three of those possible eight states contain two and only two heads. So the probability of throwing any of those three states is three in eight, or 3/8 = 0.375.

Probability of tails on each toss = 1/2Probability of tails on 3 consecutive tosses = (1/2) x (1/2) x (1/2) = 1/8Probability of NOT 3 consecutive tails = (1) minus (probability of 3 consecutive tails) = 7/8 = 87.5%

It is (1/2)3 = 1/8 or 0.125

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