Probability

Math and Arithmetic

Statistics

Top Answer

The probability of getting any outcome is 100%.

The probability of a specific outcome depends on the description of that outcome.

Some outcomes are more probable. Some are less probable.

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0The probability is 0.998

The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%

Do you mean what are all the possible outcomes? Or what is the probability of a certain outcome? Need a little more information.

The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.

It depends on how many times you toss it.

Since each event is independent, the probability remains at 0.5.

The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%

one out of 5 or 2 out of 10

1/2 chance of getting heads or tails 5 times 1/10

It is (1/2)3 = 1/8 or 0.125

There are 23 or 8 possibilities; one is HHH. So, probability of HHH is 1/8 or 0.125.

The probability of getting an even sum on two dice is 18 in 36 or 1 in 2 or 0.5. The probability of doing that three times in a row is 0.53 or 0.125.

Answer this Question : Probability of getting 10 heads in a row is(1/2)^10 = 1/1024 = 0.000976 or 0.098 %

Ideally, the probability of getting any specific combination of length n is 0.5n = 1/2n. For n = 3, this is 0.125 = 1/8.

The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.

The probability is 5/16.

If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.

One hundred percent it you toss the coin eight times.

The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954

If you continue tossing the coin forever, it is effectively a certainty. So probability = 1 If you toss it only 9 times, it is (1/2)9 = 1/512 = 0.00195 (approx)

Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.

Because a coin is two-sided, 50/50 is always the probability. Unless your coin lands on the grass (on the lawn), then it will probably land on its edge.

yes you times it then simplify

Tossing a coin ten times is a [repeated] experiment or trial. It is neither empirical nor theoretical probability.

The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.

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