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This is easiest calculated by calculating the probability that NO SINGLE heads is obtained; this is of course the complement of the question. The probability of this is 1/2 x 1/2 x 1/2 ... 7 times, in other words, (1/2)7. The complement, the probability that at least one head is obtained, is then of course 1 - (1/2)7, or a bit over 99%.

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Q: What is the probability of getting heads at least once if a fair coin is flipped 7 times?
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If you were to flip a coin 4 times what is the probability of getting heads at least one time?

As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.


What is the probability of getting a least one tail when tossing eight fair coins?

The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256


If you were to flip a coin eight times what is the probability of getting heads at least six times?

It is approx 0.1445


What is the probability of obtaining at least one head when a coin is flipped four times?

The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375


Toss a coin 3 times and what is the probability of getting at least two heads?

There are 23 or 8 possible outcomes listed below (H=Head, T=Tails). HHH HHT HTH HTT THH THT TTH TTT each has a 1/8 probability. Count the number that has at least 2 heads and it is 3. So, the probability is 3/8.

Related questions

What is the probability of getting heads at least once if a fair coin is flipped three times?

7/8


Suppose six coins are flipped then the probality of getting at least one tail?

The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.


What does at least mean in math?

'At least' means equal to or greater than. This meaning is not restricted to maths; it is one of the common everyday meanings of the phrase.So if you have a question which, for example, tells you to calculate the probability of getting at least one head when a coin is flipped twice then it means:What is the probability of getting one or more heads when a coin is flipped twice.


What is the probability of winning by getting more heads when flipping a coin once or flipping a coin twice?

Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75


What is the probability of a coin landing on heads when it is flipped 100 times?

The probability of landing on heads at least once is 1 - (1/2)100 = 1 - 7.9*10-31 which is extremely close to 1: that is, the event is virtually a certainty.


If you were to flip a coin 4 times what is the probability of getting heads at least one time?

As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.


What is the probability of getting a least one tail when tossing eight fair coins?

The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256


What is the probability of getting at least 2 heads when flipping a coin 3 times?

.125


If 5 coins are flipped what is the probability of obtaining at least one heads?

The correct answer is 31/32 or 0.96875 because .50/2/2/2/2= 3.125%


If you were to flip a coin eight times what is the probability of getting heads at least six times?

It is approx 0.1445


What is the probability of getting heads more than once if you flip a coin three times?

For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times


What is the probability of obtaining at least one head when a coin is flipped four times?

The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375