Top Answer

The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.

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0The answer depends on what the experiment is!

The probability to tossing a coin and obtaining tails is 0.5. Rolling a die has nothing to do with this outcome - it is unrelated.

The probability of getting a six on a six sided die and then getting a tails is zero. There is no tails on a die.

Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.

you are looking for the probability of getting one tail, two,......., and six this equivalent to saying 1 - the probability of not getting any tails (or getting 6 heads = (1/2)^6). P(X>=1) = 1 - (1/2)^6=

You have a 1 in 2 chance with one flip; so, 2 to the 6th power, or 1 in 2x2x2x2x2x2; a 1 in 64 chance.

Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.

Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is Â½. Similarly, the probability of getting a tail is Â½.Use Binomial to work out this problem. You should get:(5 choose 4)(Â½)4(Â½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(Â½)4 indicates the probability of obtaining 4 tails.(Â½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.

The answer to what I think the question might be, is (1/2)*(1/6) = 1/12

The probability of Tails on the first toss is 0.5 .The probability of Tails on the second toss is 0.5 .The probability of Tails on the third toss is 0.5 .The probability of Tails on the fourth toss is 0.5 .The probability of all four is (0.5 x 0.5 x 0.5 x 0.5) = 0.0625 = 6.25%

The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375

The probability of Tails on the first toss is 1/2.The probability of Tails on the second toss is 1/2.The probability of Tails on the third toss is 1/2.The probability of Tails on the fourth toss is 1/2.The probability of Tails on the fifth toss is 1/2.The probability of Tails on the sixth toss is 1/2.The probability of Tails on the seventh toss is 1/2.The probability of all of them is (0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5) = (0.5)7 = 0.0078125= 0.78125 %

They are methods of obtaining the probability of an event.

The probability is 0%. The result will be heads or it will be tails but it cannot be heads and tails.

The probability of the coin flip being heads or tails is 100%.

Probability of tails on each toss = 1/2Probability of tails on 3 consecutive tosses = (1/2) x (1/2) x (1/2) = 1/8Probability of NOT 3 consecutive tails = (1) minus (probability of 3 consecutive tails) = 7/8 = 87.5%

The second part of the question is not specific enough. Is it 3 on the roll of a die, a spin of a spinner, a card from a deck, a roulette wheel?

The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128

The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)

Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %

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