Math and Arithmetic

Statistics

Probability

567

Top Answer

75 over 2^23 (2 times itself 23 times, 2x2x2x2x2 etc...)

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0What is the chance of it landing on heads twice in a row?

The probability is 6 in 12, or 1 in 2.

The probability is 5/16.

It depends on how many times you toss it.

The probability is 0.5 regardless how many times you toss the coin."

Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.

If you have tossed a fair, balanced coin 100 times and it has landed on HEADS 100 consecutive times, the probability of tossing HEADS on the next toss is 50%.

Simple question, difficult answer. It depends on how many times you want the penny to land on heads. The probability of a penny landing on heads once is 1 in 2. For it to land on heads twice is 1 in 4, for three times it is 1 in 8, and so on and so forth.

1/2 chance of getting heads or tails 5 times 1/10

The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10

p(heads)= 0.5 p(heads)^4= 0.0625

It is (1/2)3 = 1/8 or 0.125

Answer this Question : Probability of getting 10 heads in a row is(1/2)^10 = 1/1024 = 0.000976 or 0.098 %

The probability of landing on heads at least once is 1 - (1/2)100 = 1 - 7.9*10-31 which is extremely close to 1: that is, the event is virtually a certainty.

The probability of heads is 0.5 each time.The probability of four times is (0.5 x 0.5 x 0.5 x 0.5) = 0.0625 = 1/16 = 6.25% .

The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.

There are 23 or 8 possibilities; one is HHH. So, probability of HHH is 1/8 or 0.125.

The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)

The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%

If it is a fir coin, the probability is (1/2)10 = 1/1024.

Each toss has a 1/2 probability of getting heads. Each toss is an independent event. So three heads in a row (heads AND heads AND heads) would have a probability of:1/2 * 1/2 * 1/2 = (1/2)^3 = 1/(2^3) = 1/8 = 12.5%

First event is to roll a 3 or 6 on a die, which gives you a probability of 2 out of 6. Second event is tossing a heads on a coin, so a probability of 1 out of 2. Since both chances are not related, you can multiply both chances: 2/6 times 1/2 = 1/6 = 0,166666...

If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.

It is 17C5*(1/16)5*(15/16)12 = 0.00272 approx.

If it is a fair coin, the probability is exactly 50%. The coin has no memory of what it did in the last flip. ■

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