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# What is the probability of tossing a coin 9 times and getting at least one tail?

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The probability of tossing a coin 9 times and getting at least one tail is:

P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%

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## Related Questions

The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 &asymp; 3.13%

The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.

Because a coin is two-sided, 50/50 is always the probability. Unless your coin lands on the grass (on the lawn), then it will probably land on its edge.

The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954

The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.

The probability of getting any outcome is 100%.The probability of a specific outcome depends on the description of that outcome.Some outcomes are more probable. Some are less probable.

There are 23 or 8 possibilities; one is HHH. So, probability of HHH is 1/8 or 0.125.

The probability of getting an even sum on two dice is 18 in 36 or 1 in 2 or 0.5. The probability of doing that three times in a row is 0.53 or 0.125.

Answer this Question : Probability of getting 10 heads in a row is(1/2)^10 = 1/1024 = 0.000976 or 0.098 %

Ideally, the probability of getting any specific combination of length n is 0.5n = 1/2n. For n = 3, this is 0.125 = 1/8.

There are 2^5 (2*2*2*2*2), or 32, possible outcomes of tossing a coin 5 times. Only one of those outcomes does not contain any tails. This leaves us with 31/32, or 97% chance of at least one toss coming up tails.

The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.

If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.

One hundred percent it you toss the coin eight times.

If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8

If you continue tossing the coin forever, it is effectively a certainty. So probability = 1 If you toss it only 9 times, it is (1/2)9 = 1/512 = 0.00195 (approx)

The probability of getting an even number on at least one of the 3 rolls is 7/8.

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