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Answer this Question : Probability of getting 10 heads in a row is

(1/2)^10 = 1/1024 = 0.000976 or 0.098 %🙏

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0It depends on how many times you toss it.

1/2 chance of getting heads or tails 5 times 1/10

It is (1/2)3 = 1/8 or 0.125

The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%

There are 23 or 8 possibilities; one is HHH. So, probability of HHH is 1/8 or 0.125.

The probability is 5/16.

Each toss has a 1/2 probability of getting heads. Each toss is an independent event. So three heads in a row (heads AND heads AND heads) would have a probability of:1/2 * 1/2 * 1/2 = (1/2)^3 = 1/(2^3) = 1/8 = 12.5%

Ideally, the probability of getting any specific combination of length n is 0.5n = 1/2n. For n = 3, this is 0.125 = 1/8.

The probability is 0.998

If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.

The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%

If you have tossed a fair, balanced coin 100 times and it has landed on HEADS 100 consecutive times, the probability of tossing HEADS on the next toss is 50%.

The probability of flipping a coin 3 times and getting 3 heads is 1/2

If you continue tossing the coin forever, it is effectively a certainty. So probability = 1 If you toss it only 9 times, it is (1/2)9 = 1/512 = 0.00195 (approx)

The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.

The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.

The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238

252/1024 or 0.246. One method of calculating it is this: The total number of outcomes possible by tossing a coin 10 times is 2 to the 10th, which is 1024. In addition, getting 5 heads in 10 tosses is like arranging 5 identical objects in 10 spaces (the remaining 5 spaces are by default Tails), which can be done in 10C5 ways, which is 252. So the probability of getting 5 heads is 252/1024.

Since each event is independent, the probability remains at 0.5.

The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.

The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)

75 over 2^23 (2 times itself 23 times, 2x2x2x2x2 etc...)

one out of 5 or 2 out of 10

the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.

Take your base chance of getting heads, 1/2, and raise it to the power of the number of times you flip the coin, 4. (1/2)4 = 1/16 = .0625 = 6.25 %

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