Math and Arithmetic

Statistics

Probability

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Top Answer

For each toss, the probability that it'll land heads up is 1/2

So 1/2 * 1/2 * 1/2 = 1/8, or .125

There is a 12.5% chance that it will land heads-up all 3 times.

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0The probability of the coin flip being heads or tails is 100%.

No heads means that every toss lands tails. (0.5)30= 9.3 x 10-10 Note that 109 = 1 trillion, so the probability can be stated this event is likely to occur about 9 times in 10 trillion tosses.

If it is a fair coin, the probability is 1/2.

1/2, or 50% since you are only asking what the probability of the last outcome is.

-- There are (2 x 2 x 2 x 2) = 16 possible outcomes of four tosses.-- There are three successful cases:H H T TT H H TT T H H-- So the probability is 3/16 or 18.75% .

Since it is a fair coin, the probability is 0.5

It means just what it seems to -- someone tosses a coin up and you try to guess which side will be facing up when it lands. "Heads" is the side with the person's face on it and "tails" is other side.

1/2 (equal to 0.5, or 50%).

Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.

The odds of each coin toss are 50-50. The coin has no memory; there is no record of what the last four tosses are. EVERY toss is at 50-50 odds.

An outcome is what actually happens, while the probability of that outcome is how likely that particular thing is to happen. Say I was flipping a coin. The probability of the outcome of heads is 1/2 because there are 2 possible outcomes and heads is only 1 of them. Then when I flip the coin, it lands on tails. The outcome is tails.

Any time there are two options, heads or tails when you flip a coin for example, the probability is 1/2, that the result will be either one option, or the other. The expected result when the coin lands is a 1/2 probability that it will be heads, and a 1/2 probability that it will be tails. What "1 out of 2 failing" means is that for every two students that take an exam, for example, one of them will fail. Of course, it also means, that 1/2 will pass.

The probability that the coin lands on the heads ones: 1/2Two times (1/2)^2 = 1/4Five times (1/2)^5 = 1/32 (so 1 in 32 attempts)n times (1/2)^n

First, note that one even is independent of the other. If A and B are two independent events, the probability of A and B, written P(A and B) is P(A)xP(B). So if event A is the probability of a 5, P(A)=1/6 and if B is heads, P(B)=1/2 So P(A and B)=1/6 x1/2=1/12

A biased probability is one where not every outcome has the same chance of occurring. A biased coin is one where one side, the "heads" or "tails" has a greater probability than the other of showing. A coin which has a centre of gravity closer to the tails side than the heads side would be biased in that heads is more likely to show than tails. The size of coin can have an effect on the probability of heads and tails - during the Royal Institute Christmas lectures in the 1990s demonstrating probability a large version of the pound coin was made to be able to allow the audience to see it being tossed - on the broadcast (and tape) version it landed and stayed on its edge! showing the probability of heads = tails ≠ ½; the probability of heads = probability of tails, but they are actually slightly less than ½ as the coin could land on its edge and stay there - with a standard size coin, if it lands on its edge it takes very little for the centre of gravity to shift outside the base of the edge and for the coin to fall over, but with a very large similar coin (ie one scaled up [proportionally] in lengths) it can take quite a bit before the centre of gravity goes outside the base if it lands on its edge which forces it to fall over (plus there will be a "significant" rise in the centre of gravity to do so, thus favouring stability on an edge which does not exist in the standard, small, sized version of the coin).

The event is that the coin lands with the Heads on top.

If p is the probability that any one toss lands on "heads", the probability that exactly 4 toss out of 8 lands on head is this: p^4 * (1-p)^4 * C(4,8) Where C(k,n) is an old notation for n! / ( k! * (n-k)! ) So C(4,8) = 8! / ( 4! * 4!) = 8*7*6*5 / 24 = 70 If your coin is well balanced, p is 50% and you get your answer: (0.5)^8 * 70 = 70/256 =~ 27,34%

When you toss a coin and it lands on its edge.

You roll it many times. The probability that it lands on a six is the number of times that it lands on a six divided by the number of times the die has been rolled.

It is 10C3*(1/2)10 = 10*9*8/(3*2*1)*(1/1024) = 0.1172, approx.

If two events are disjoint, they cannot occur at the same time. For example, if you flip a coin, you cannot get heads AND tails. Since A and B are disjoint, P(A and B) = 0 If A and B were independent, then P(A and B) = 0.4*0.5=0.2. For example, the chances you throw a dice and it lands on 1 AND the chances you flip a coin and it land on heads. These events are independent...the outcome of one event does not affect the outcome of the other.

yes! after his campaign in rajput lands

You can write flip a coin if it lands on heads your bad at flipping if it lands on tails your cheating or your hair will turn green or

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