Math and Arithmetic

Statistics

Probability

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The probability that a coin will result in heads in any one toss is 1/2. If you toss the coin three times, the probability that the coin will turn up heads each time is 1/2 x 1/2 x 1/2 or 1/8, which is 12.5%.

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0The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.

The probability of tossing heads on all of the first six tosses of a fair coin is 0.56, or 0.015625. The probability of tossing heads on at least one of the first six tosses of a fair coin is 1 - 0.56, or 0.984375.

If the coin is fair, the probability of getting all heads will decrease exponentially towards 0.

With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%

The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.

For each toss, the probability that it'll land heads up is 1/2 So 1/2 * 1/2 * 1/2 = 1/8, or .125 There is a 12.5% chance that it will land heads-up all 3 times.

1/2 x 1/2 x 1/2 = 1/8 The probability is 1 chance in 8 sequences, or .125

The probability of getting all heads is 1/24 = 1/16 The probability of getting all tails is also 1/24 = 1/16 The probability of all heads or all tails is the sum of the two = 1/8

0.5*0.5*0.5 = 0.125 or 1/2*1/2*1/2 = 1/8

To find P( at least 1 head in 7 tosses) we can find P( no heads) and subtract that from one. Alternatively, we need to find P ( 1 head) + P ( 2 heads )+...+ P(7 heads) Since P of no heads is P( all tails) this is (1/2)7 =.0078125 ( 1/128 as a fraction) Now 1-(1/128)=127/128 or .9921875

50-50. each toss is independent of any previous toss. if all tosses are to be heads/tails then each toss you multiply by the number of chances. i,e. 2, starting with 1. three heads in a row is 1x2x2

For 4 coin tosses, there are 16 possible outcomes. Tails on 75% of 4 tosses is 3 times tails, and 1 time heads. This occurs in 4 of those 16 possibilities, so the probability is 4/16 = 1/4 (or 25%). But if the question is 'what is the probability that it's tails at least 75% of the time, then you have to add in the 1 where all 4 are tails, then you have 5/16 (or 31.25%).

I don't know! I asked you!

1/2 apex It does not matter what each prior flip's result was. Each flip has a probability of 0.5 heads or tails. Coins do not have "memory".

The probability of getting all heads or all tails in 5 flips of a coin is 1 in 16.The probability of getting a head or a tail on the first flip is 1 in 1. The probability of each of the following coins matching the first coin is 1 in 2. Simply multiply the five probabilities (1 in 1) (1 in 2) (1 in 2) (1 in 2) (1 in 2) and you get 1 in 16.It is true that the probability of getting all heads is 1 in 32, and the probability of getting all tails is also 1 in 32. Since the question asked the probability of both cases (all heads or all tails), the answer is 1 in 16.

The probability of the first coin landing heads is half (or 1/2). Similarly, the probability of the second and third coins landing heads are also 1/2 in each case. Therefore, the probability of having three heads is: (1/2)(1/2)(1/2) = (1/8)

This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.

That's the same as the total probability (1) minus the probability of seven heads. So: 1 - (1/2)7 = 127/128

If the sequence matters (you want H-H-T in that order), then . . .Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%=====================================================If the sequence doesn't matter, then the probability is higher.All the possible results of 3 tosses are:TTTTTHTHTTHHHTTHTHHHTHHHIf the sequence doesn't matter, there are 3 different ways to get 2 heads and 1 tail.The probability is3/8 = 0.375 = 37.5%

There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?

Probability determined as part of an experiment is called experimental probability. Probability determined by analysis of all of the possible and expected outcomes is called theoretical probability.

The probabilty of you flipping 3 coins and getting all heads or tails is 0.125 or 1/8.

If they are fair coins, it is 1/16.

The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)

3/8, or 37.5%There are eight possible sequences that can emerge from three coin tosses. Three have heads twice and tails once. Three have the opposite, two tails and one heads. The remaining possibilities are all heads or all tails.H H TH T HT H HT T HT H TH T TH H HT T T

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