Math and Arithmetic
Statistics
Probability

# What is the probability that exactly two times head are being tossed?

The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once!

Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25.

If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.

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## Related Questions

Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.

The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5

There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?

The probability of a one being rolled in a fair die is 1 in 6, or 0.1666... . The probability of a one not being rolled is 5 in 6, or 0.8333... . The probability, then, of exactly one one being rolled in nine rolls is 1 in 6 times 5 in 6 to the 8th power, or about 0.0388.

If the coin is fair and balanced, like Fox, then the probability is 50%.

The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.

0.5, 1/2, 50% The probability for heads versus tails does not change based on the amount of times the coin is tossed. It will always be a 50% chance.

you have 63 chances out of 64. i once witnessed a coin being tossed seven times and giving up 7 consecutive heads. we never tried it an eighth time, 7 heads and you had to go to the bar.

Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails &amp; 1 Head. They are: TTTH, TTHT, THTT, and HTTT.

The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.

Each coin toss is a Bernoulli trial with a probability of success of .5. The probability of tossing heads exactly 3 times out of five is3 ~ Bin(5, 1/2), which equals(5!/(3!(5-3)!))(0.5^3)(1-0.5)^(5-3), which is 0.3125.

(1/2)^3 = 1/8th Since the initial probability (assuming independence) of getting a head in a single toss is one half (1/2) we just cube this probability because of the number of events we are performing. So if you were to try to calculate the probability of a coin being tossed 6 times it would be one half to the 6th power which is 1/64.

25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25

If a fair coin is tossed 5 times, the probability of getting 5 heads is:P(H,H,H,H,H) = (1/2)5 = 1/32 = 0.03125 = 3.125% &acirc;&permil;&circ; 3.1%

If you have tossed a fair, balanced coin 100 times and it has landed on HEADS 100 consecutive times, the probability of tossing HEADS on the next toss is 50%.

The mathematical probability of getting heads is 0.5. 70 heads out of 100 tosses represents a probability of 0.7 which is 40% larger.

The probability of the coin coming up heads each time is 1/8; likewise for 3 tails. The probability of getting 2 heads and 1 tail (in any order) or 2 tails and 1 head, is 3/8. There are lots of other events whose probability can be calculated when a coin is tossed 3 times, but the question doesn't specify what event is to have its probability calculated.