The probability is 1/2^4 = 1/16
The conditional probability is 1/4.
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
There are 8 permutations of three coins. Of these, 3 of them have two heads, so the probability of tossing two heads on three coins is 3 in 8, or 0.375. However, you said, "at least", so that includes the case of three heads, so the probability of throwing at least two heads is 4 in 8, or 0.5. T T T T T H T H T T H H * H T T H T H * H H T * H H H *
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
Take your base chance of getting heads, 1/2, and raise it to the power of the number of times you flip the coin, 4. (1/2)4 = 1/16 = .0625 = 6.25 %
Tossing two coins doesn't have a probability, but the events or outcomes of tossing two coins is easy to calculate. Calling the outcomes head (H)or tails (T), the set of outcomes is: HH, HT, TH and TT as follows: 2 heads = (1/2) * (1/2) = 1/4 1 head and 1 tail, can be heads on first coin tails on second, or just the opposite, there's two possible events: (1/2)*(1/2) + (1/2)*(1/2) = 1/2 2 tails = same probability as two heads = 1/4
Coin tosses are what we call Independent Events, meaning that the results of one toss have no effect on the next toss or any thereafter. Therefore the probability of each toss is 1/2. If, however, you want to know the probability of tossing two coins, and each coin landing heads-up, you simply multiply their probabilities together, resulting in 1/4.
The probability for that is (1/2)4 = 1/16.
It is certainly possible. The probability is 1/4.
By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%
If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.
If you toss the coins once only, it is 1/4.
The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)
75% The chance of not having a tails but a heads on both coins is (1/2)2 or 25%, so the chance of actually having a tails on either coin is 3/4, or as a percentage 75% .
The probability of tossing two coins one time and not getting two heads is 3/4 or 75%. The possible out comes of this are: HH, HT, TH, TT. There is only one way to get two heads, out of four possible results. Another, faster way to do this problem would be to multiply the probability of getting one head on one coin (1/2) by the probability of getting a head on another coin (also 1/2). This will result in 1/4. Because you want every result BUT this one, subract this answer from one. You will get the an answer of 3/4. This may not seem like a faster method when writing it out, but with a larger number of coins it would save a lot of time, because you do not have to go through all of the combinations.
The probability of tossing a 4 is 1 out of 6 sides, or 1/6. Hope this helps!
1/2 chance of getting heads or tails 5 times 1/10
4C2(1/2)4 = 6/16 = 3/8