Assuming they are fair, regular dice, the probability is 1/18.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
It is 5/6.
I think it means something that happens at the same time as another. A probability thing. Like: roll a dice for odds and pull a queen of hearts out of a deck of cards.
You can't, can you? The smallest number that you can roll with four dice is four, that is, a 'one' on each of the four dice.
No. Each roll is independent of the previous roll (on a fair dice). The same is true for flipping a coin. Getting a six your first roll does not make you any more or less likely to roll a six the second time.
It is 7/12.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
Assuming that "to" should actually be "two", Since the outcome on each die is independent, Pr(Roll a prime when rolling two dice) = Pr(Roll a prime on a die)2 = (1/2)2 = 1/4
If using regular dice, the probability is 0 since the minimum sum from four dice is 4.
2/12 or 1/6
It is 5/6.
Probability zero. If both dice have the same number, then the result will be even. If both dies are odd (as in the case of 5) then the sum is even. If both dies are even, the sum is also even. The only way to get an odd sum is to have one die have an odd number and the other die have an even number. That will happen 50% of the time.The probability of both dice showing 5 is 1/36. But the two events will never happen at the same time.
I think it means something that happens at the same time as another. A probability thing. Like: roll a dice for odds and pull a queen of hearts out of a deck of cards.
You can't, can you? The smallest number that you can roll with four dice is four, that is, a 'one' on each of the four dice.
No. Each roll is independent of the previous roll (on a fair dice). The same is true for flipping a coin. Getting a six your first roll does not make you any more or less likely to roll a six the second time.
The probability that one die will not be a 3 is 5/6The probability that all will not be 3 is ((5/6)4)If you roll 4 dice, there are 5 possible outcomes (for this problem).There will be NO 3's, there will be one 3, there will be two 3's. there will be three 3's, or, there will be four 3's. Add all possible probabilities = 1. At least one meanse either 1,2,3, or 4 3's but NOT one.So the prob of at least one = total prob - prob of NO1- (5/6)4 = 1 - 625/1296= 671/1296
Half the time!