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Let say the dice has n sides

Let first search for the probability to roll a number less or equal to 2

Probability to roll a 1 = 1/n

Probability to roll a 2 = 1/n

Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2

= 1/n + 1/n = 2/n

Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2)

= 1 - 2/n = (n-2)/n

If n = 6 then the result is (6-2)/6 = 4/6 = 2/3

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Q: What is the probablity of rolling a number greater than 2 on one roll of a die?
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