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What is the product of the prime factors of 117?

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2010-05-04 13:06:38
2010-05-04 13:06:38

The product of the prime factors of any number is equal to the number itself. In the case of 117, its prime factorization is 32 x 13.
The prime factors are: 3 and 13. (3 x 13 = 39)

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Related Questions


To find the product of the prime factors of 117, you can use a factor tree. 117 39,3 13,3,3 3 x 3 x 13 = 117 However, the product of the prime factors of any number is the number itself.



As a product of its prime factors: 3*3*13 = 117 or as 3^2*13 = 117


The factors of 117 are: 1 3 9 13 39 117The prime factors are: 3 13



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If the question is, "What are the prime factors of 117?" Then , 117 = 3 x 3 x 13 = 32 x 13


117 is not a prime number because it has more than two factors. It is divisible by 3, 1, 117, 39 etc.


117 is not a prime number. Its positive integer factors are as follows:1, 3, 9, 13, 39, 117No. In addition to '1' and itself, 3, 9, 13, and 39 are also factors of 117.


prime numbers of 234 = 2, 3, 13


117 Is A Number Composite # which means that has more than 2 factors the factors for 117 are=>1, 3, 9, 13, 39, 117 if you add the digits 1+1+7=9 => 9 / 3 there for 117 is/ by 3 1+1+7=9 => 9/9 there for 117 is / by 3 (: 3, 9, 13, 39The factors of 117 are: 1 3 9 13 39 117The prime factors are: 3 13


The prime factorization of a number is writing it as a product of its prime factors.


As a product of its prime factors: 2*2*2*5 = 40 As a product of its prime factors: 2*2*2*7 = 56 As a product of its prime factors: 3*13 = 39



215 as the product of prime factors can be represented as 215 = 5x43



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