Here is the half equation for this reaction between sodium ethandioate and potassium manganate: 2MnO4- + 5C2O42- + 16H+ = 2Mn2+ + 10CO2 + 8H2O Carbon dioxide gas, water and sodium permanganate (a manganese (II) salt) is produced.
when potassium permanganate and ethelyene glycol (anitfreeze) are mixed in the right ammounts a thermal reaction takes place in a survival situation this can be used to start a fire, mix the two chemicals together wrapped in a piece of paper, card, cloth, cotton wool
ethene is oxidized by potassium manganate 7 KMnO4 into CH3COOH or ethanoic acid
C2H2 + KMnO4> C2H2(OH)2 +MnO2 + KOH
you try to balance this equation
The product of the reaction between cyclohexene and hot acidified potassium manganate 7 will be cyclohexan-1,2-diol. Two hydroxy groups will bond at the site of the double bond.
The half equation for the reduction of carbon dioxide to methanoic acid and its standard electrode potential value is given as: CO2 + 2H+ + 2e- gives HCOOH EO = -0.11 V The half equation for the reduction of ACIDIFIED potassium manganate(VII) and its standard electrode potential value is given as: MnO4- + 8H+ + 5e- gives Mn2+ + 4H2O EO = +1.51 V Thus, the standard electrode potential E for the overall reaction is: E = 1.51 - (-0.11) = +1.62 V Since it is positive (and well positive), the oxidation of methanoic acid by potassium manganate(VII) can take place under standard conditions. The overall equation (obtained by balancing the number of electrons) is: 2MnO4- + 6H+ + 5HCOOH gives 2Mn2+ + 8H2O + 5CO2
the reaction between bleach anb potassium iodide is KI+NaCl2--->KCl2+NaI
potassium bromide + fluorine --> potassium fluoride + bromide
Potassium chloride
acidified means that its chemical properties may be acidic in nature and since it is heated, it is more reactive..!
The product of the reaction between cyclohexene and hot acidified potassium manganate 7 will be cyclohexan-1,2-diol. Two hydroxy groups will bond at the site of the double bond.
ethanal
ethanol is converted into acetic acid....
The half equation for the reduction of carbon dioxide to methanoic acid and its standard electrode potential value is given as: CO2 + 2H+ + 2e- gives HCOOH EO = -0.11 V The half equation for the reduction of ACIDIFIED potassium manganate(VII) and its standard electrode potential value is given as: MnO4- + 8H+ + 5e- gives Mn2+ + 4H2O EO = +1.51 V Thus, the standard electrode potential E for the overall reaction is: E = 1.51 - (-0.11) = +1.62 V Since it is positive (and well positive), the oxidation of methanoic acid by potassium manganate(VII) can take place under standard conditions. The overall equation (obtained by balancing the number of electrons) is: 2MnO4- + 6H+ + 5HCOOH gives 2Mn2+ + 8H2O + 5CO2
No reaction.
the reaction between bleach anb potassium iodide is KI+NaCl2--->KCl2+NaI
No reaction occurs between the acidified hydrogen peroxide and the other halide ions, because the hydrogen ions involved in both cases are in the same group. For a reaction to occur it needed to have an element that is more reactive than hydrogen.
potassium bromide + fluorine --> potassium fluoride + bromide
This reaction doesn't occur.
Exothermic
Potassium chloride