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Answered 2014-03-18 12:12:19

The product of two consecutive integers is 132. Find the two integers.

They are: 11*12 = 132

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11 & 12 are the integers whose product is 132.



3 consecutive even integers whose sum is 396 are 130, 132 and 134.


Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.


X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45



Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.


The lowest common multiple (L.C.M) of 11 and 12 is 132. The LCM of any two consecutive integers is always their product.Their product.Their product.


what equals 132 is 12*11=132


The question refers to two factors of 132 that are consecutive integers. The answer is 11 & 12, as 11 x 12 = 132 This can be solved as follows. Let n be the smaller of the two numbers then (n + 1) is the other number. n(n + 1) = 132 n2 + n = 132 n2 + n - 132 = 0............which can be factored as (n + 12 )(n - 11) = 0 As we are only concerned with the positive integer result then this occurs when n - 11 = 0, that is when n = 11, thus (n + 1) = 12. NOTE : Integers can also be negative and this applies to the other solution when n + 12 = 0, so n = -12 and consequently (n + 1) = -11 giving the result that -12 x -11 = 132.


The three integers are ±13, ±15, and ±17. The difference between ±132 and ±172 is equal to 289 - 169 = 120.


132 is the LCM (lowest common multiple) of 44 and 132. 132 divided by 132 equals 1, and 132 divided by 44 equals 3.


It is: -11 times 12 = -132


It is not possible in our Universe that two consecutive numbers can total an even number, since any two consecutive numbers must be an odd and an even (or vice versa). There are two consecutive odd numbers which total 132 ie 65 and 67


Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.


They are sets of integers such that the sum of the squares of two of the numbers equals the square of the third. For example, 5, 12 and 13 where 52 + 122 = 132


No. All integers are rational numbers.


philadelphia phillies this year (2010) with 130 consecutive or 132


Answer:12y=132y=132/12=11


132/3 = 4444 x 3 = 132


The ANSWER for 132 divided by 11 is 12.




It doesn't ! 132+141=273



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