6 m/s divided by 12 s or 0.5 m/s^2. (a half meter per second per second)
(on average)
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
Kilometers/hour2. Note that for this kind of calculation, it is much more common to measure distances in meters, time in seconds, velocity in meters/second, and acceleration in meters/second2.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
Kilometers/hour2. Note that for this kind of calculation, it is much more common to measure distances in meters, time in seconds, velocity in meters/second, and acceleration in meters/second2.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
The differences are that acceleration refers to the rate of change in velocity of an object while velocity is the rate of displacement of an object, and acceleration is measured in meters per squared seconds while velocity is measured in meters per second. On the other hand, they both use time as a component and they are both vectors in nature.
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2
a=change over velocity/time 60-initial velocity 45-final velocity 45-60= 15m/s 15/5= 3- acceleration
Acceleration = (Change in speed)/(Time) a = (v-u)/t = (500-1000)/5 = -500/5 = -100 Acceleration is -100 ms-2
Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.
acceleration = change in velocity divided by timeaccel = (9-3)/3 = 6/3 = 2 meters per second per second