It depends on the parents. The parent could have two dominant genes which would give a 0% chance of the offspring being recessive. The only way that the offspring could have a recessive characteristic is if the both parents have one dominant and one recessive gene, a 25% chance. The chance that both parents would pass on the recessive gene (if they have one dominant and recessive gene) is also 25%, because there is a 50% chance for each parent.
25% homozygous dominant
50 % heterozygous (with a dominant phenotype)
25% homozygous recessive
It 0
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
If both the individuals are heterozygous dominant then the probability of recessive (homozygous) phenotypic offspring would be 1:4
They are the same
100% heterozygous dominant
a homozygous trait is when an offspring has either both dominant genes or both recessive genes from its parents. a heterozygous trait is when an offspring has both dominant and recessive genes. for example: a long-tailed cat is dominant and a short-tailed cat is recessive. the long-tailed cat (homozygous dominant) had offsprings with the short-tailed cat (homozygous recessive). by doing the punnett square, 100% of their offspring will be heterozygous.
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
well, it depends on the genes of the parents
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
25%
100 percent.
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
Homozygous
A cross between a homozygous recessive and an individual of unknown genotype is called a test cross.The homozygous recessive can only pass on a recessive allele to the offspring, and so any recessive in the other parent will show up in the phenotype (detectable characteristics) of some of the offspring.