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The oxidation half-reaction is: Fe => Fe+3 + 3e-, and the reduction half-reaction is: F2 + 2e- => 2 F-1.

For a complete equation, the oxidation half-reaction as written must be multiplied by 2 and added to the reduction half-reaction as written multiplied by 3 to result in an overall reaction of 2 Fe + 3 F2 = 2 FeF3.

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12y ago
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10y ago

Oxidant half reaction:

2H+ + 2e- --> H2

Reductant half reaction:

Fe --> Fe2+ + 2e-

Tribune ions:

2Cl- --> 2Cl-

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Wiki User

8y ago

Ox. 2H+ + 2e- --> H2

Red. Fe --> Fe2+ + 2e-

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8y ago

The reaction is:
Fe + 2 HCl = FeCl2 + H2

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7y ago

Fe(s) + 2HCl(aq) ==> FeCl2(aq) + H2(g)
Fe(s) ==> Fe^2+(aq) + 2e- (oxidation)
2H^+ +2e- ==>H2(g) (reduction)

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10y ago

Fe(s)->Fe2+2e-

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8y ago

Fe(s) > Fe2+ + 2e-

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Anonymous

Lvl 1
3y ago

Fe(s)--Fe2+ 2e- is the right answer.

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Q: What is the oxidation half reaction for Fe(s) 2HCl(aq) FeCl2(aq) H2g?
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