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121.760

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Bennett Bode

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1y ago
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9y ago

Antimony is a meta element. Atomic Mass of it is 121. Atomic number of it is 51.

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15y ago

Very close to 11.0g/cm³. 5% antimonial lead is 10.92g/cm³ and 10% antimonial lead 10.50g/cm³.

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16y ago

6.61 - 6.72, Average = 6.66

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11y ago

6.61

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Q: What is the density of lead with 2 percent antimony?
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What is the empirical formula of a compound that is 50.7 percent antimony and 49.3 percent selenium by weight?

We assume 100 grams of the compound and turn those percentages into grams and get the moles. 50.7 grams antimony (1 mole Sb/121.8 gram) = 0.41626 moles antimony ================================ Now, the smallest mole number (antimony) becomes 1 and the other number is divided by it(antimony) to get the empirical numbers. 0.62467 moles Se/0.41626 moles Sb = 1.5 ----------------so, this happens sometimes and this is what we do (SbSe1.5)*2 = Sb2Se3 -----------------The empirical formula Antimony selenide


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The density of lead is 11.34 g/cc Therefore the volume of 2 g of lead will be 2/11.34 = 0.1764 cc


How do you calculate percent abundance for antimony?

The atomic mass of an element is the weighted average of the masses of its isotopes. You know that: Antimony-121 has a mass of 120.9038 u, x% abundance Antimony-123 has a mass of 122.9042 u, y% abundance There are only 2 isotopes for antimony and their percent abundances should add up to 100%. In other words: x% + y% = 100% y = 1-x (percentages written as decimals) So, now let's put everything together. In order to calculate the atomic mass, multiply the percent abundance of an isotope by its atomic mass; then add the product of all the isotopes: (Atomic Mass of Antimony-121)(Percent Abundance of Antimony-121) + (Atomic Mass of Antimony-123)(Percent Abundance of Antimony-123) = Atomic Mass of Element Antimony (120.9038 amu)(x) + (122.9042 amu)(y) = 121.760 amu Replacing 1-x for y gives: (120.9038 amu)(x) + (122.9042 amu)(1-x) = 121.760 amu Solve for x: 120.9038x + 122.9042 -122.9042x = 121.760 amu -2.0040x = -1.1442 x = 0.57096 = 57.096% Solve for y: y = 1 - x y = 1 - 0.57096 = 0.42904 = 42.904%


What is the density of 2 percent milk?

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What would happen if lead -206 lost 2 protons and 2 neutrons?

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