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we have this 1/Re = (1/R1)+(1/R2) for calculating the effective resistance when resistances are connected in parallel

so the answer would be Re =( 70*30) / (70+ 30)

= 21 ohms

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14y ago
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12y ago

70 ohms and 30 ohms in parallel have a combined effective resistance of

( 1/70 + 1/30 )-1 = (70 x 30)/(70 + 30) = 2100/100 = 21 ohms

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Q: What is the resistance of 70ohms and 30 ohms in a parallel circuit?
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There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?

-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.


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A circuit contains two devices that are connected in parallel if the resistance of one of these devices is 12 ohms and the resistance of the other device is 4 ohms the total resistance of the two devi?

The net effective resistance of the parallel devices is the reciprocal of (1/12 + 1/4). Hence 3 ohms.=============================================(Which actually looks strangely similar to the first answer above.Could it be just coincidence ? I wonder . . . )


What is Resistance of 20 ohms and 10 ohms?

Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).


What is the total resistance of a 6-ohm resistor and a 12-ohm resistor in a parallel series?

In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms

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