V=IR since the load is pure resitance, R=V/I => 120/8 = 15 ohm
Volts.
We know that Voltage = Current x Resistance, so if E = I x R, then E = 20 x 12 = 240 volts, and the dryer must be plugged into a 240 volt outlet.
The formula you are looking for is R = E/I.
Given R=? I=12 ampere V=120 Volts equation I=V divided R Solution; R=12 ampere 120 Volts answer (10)
The formula you are looking for is I = E/R. Amps = Volts/Resistance.
I can't do all the math for that but if it helps that's a 1,077.3 watt heat discharge.
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
Power (Watts) = Current (Amps) * VoltagePower = 22Amps * 240 VoltsPower = 5,280 Watts5280
Power = Volts * current [p = E*I]; 120volts*10amps = 1200watts
Watts are a unit of power and Volts are a unit of electric potential, so they cannot be directly compared. However, Watts and Volts can be related byWatts = Volts * AmperesorWatts = (Volts^2) / Ohmswhere Amperes are a unit of current and Ohms are a unit of resistance. So, for example, if a lightbulb draws .333 Amps of current at 120 Volts, it is a 40 Watt bulb. (.333 A * 120 V = 40 W)
A battery is rated to supply a certain number of volts. However, it actually supplies less, because they are "lost" as the current has to get out of the battery in the first place.(The battery has internal resistance)The amount of lost volts depends on the current being drawn:The less resistance a circuit has, the more current is drawn, because it's easier to flow.Example:If the circuit has little resistance, it draws a large current and the battery's internal resistance causes more lost volts.If the circuit has high resistance, it draws a small current and there are fewer lost volts.This is why when you short-circuit a battery (give it hardly any resistance to go through) it heats up and may explode. A large current is drawn and all the volts are used by the battery's internal resistance.
Resistance is the opposition to the flow of electric current through a conductor. It is defined as the ratio of the potential difference (volts) between the ends of the conductor to the magnitude of the current (amps) through the conductor.