You have .07 Liters of 3 moles/Liter of Na2CO3. So if you do .07*3*2 (you multiply by two because there are TWO Na+ ions in Na2CO3) you get .42 moles of Na+. Then you do the same with NaHCO3. So, .03*1 is equal to .03 moles of Na+. Adding .42 with .03 will give you .45, the number of moles of Na+ of the whole solution. Since you are looking for concentration (which is moles if solute divided by Liters of solution), you must divide by .1 Liters (you get that by adding .07 and .03 of the two liquids that compose the solution) to get 4.5 Molar. That is the answer!
You need to mention the unit for 2,61.
A 0.5N Na2CO3 used in determining the concentration of an unknown HCl solution has a weight of 1.06 grams. To find the weight, you need to first find out how many moles there are by calculating molarity times volume.
Balanced equation first, last and always! Na2CO3 + 2HCl - > 2NaCl + CO2 + H2O 2.5 g Na2CO3 ( 1 mole Na2CO3/105.99 g)(2 mole HCl/1 mole Na2CO3) 0.04717 moles HCl -------------------------Now, Molarity = moles of solute/liters of solution or, for our purposes liters of solution = moles of solute/Molarity Liters HCl = 0.04717 moles HCl/0.60 M HCl = 0.0786 liters (1000 milliliters/1 liter) = 78. 6 milliliters HCl solution needed
1 Na2CO3 --Δ--> 1 Na2O + 1CO2
difference between 0.50mol na2co3 anf 0.50 M of na2co3
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
the chemical formula of washing soda is Na2CO3 (Sodium carbonate).
ar of na2co3
MnSO4+Na2CO3
1 mole Na2CO3 = 105.98844g 0.577mol x 105.98844g/mol = 61.2g Na2CO3
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
The Kb of Na2CO3 is equal to 2.1 x 10^-4. Carbonate ion is the ion that results from the dissociation of Na2CO3.