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Glycine intracts with one mole of Bezoyl chloride in the presence of 10% (w/v) solution to yield hippuric acid with the elimination of one mole of hydrochloric acid. The excess of 10% NaOH solution serves two purposes, first; to remove unreacted benzoyl chloride. The NaOH solution hydrolyses the excess of benzoyl chloride present in reaction mixture, thereby resulting in formation of sodium chloride and sodium benzoate, which being water soluble remains in solution. Secondly the hydrochloric acid eliminated reacts with NaOH to yield NaCl. Both sodium benzoate and sodium chloride are water soluble, whereas the desired product hippuric acid being insoluble may be separated easily.

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Q: What is the role of NaOH in the formation of hippuric acid?
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