Points: (1, 2) and (0, -2)
Slope: 4
Equation: y = 4x-2
Choose the equation of the line that contains the points (1, -1) and (2, -2).
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Points: (0, 5) and (5, 8)Slope: 3/5Equation: y = 3/5x+5 in slope intercept form
Answer this question… What is the slope of the line that contains the points (-1, 2) and (4, 3)?
y = 2x + 1.
Choose the equation of the line that contains the points (1, -1) and (2, -2).
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
It has no equation as such because plotting the line on a grid will produce a vertical straight line parallel to the y axis.
If you mean points of (-3, 2) and (5, -5) then the equation works out as 8y = -7x-5
Points: (3, -6) and (-3, 0) Slope: -1 Equation: y = -x-3
Points: (3, 0) and (0, -9) Slope: 3 Equation: y = 3x-9
The equation of this line is x=8 and it is my understanding that the slope is infinite/undefined.
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
y = -3x + 5