What is the slope of the line that contains the points -2 1 and 0 -3?
The slope is (y2 - y1)/(x2 - x1) = (-3 - 1)/(0 + 2) = -4/2 = -2
No. A horizontal line has a slope of 0. A vertical line has an undefined slope. Let's say you have a vertical line with the points (3,-2) and (3,4). The slope is (y1-y2)/(x1-x2) = (-2-4)/(3-3) = -6/0 = undefined. Notice that x is the same for both points. A line in which all points have the same value for x is a vertical line and as such has an undefined slope.
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate…