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There are infinitely many prime numbers, and also infinitely many twin primes so there is no answer to the question.

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Q: What is the smallest numbers whose prime factors are the consecutive prime number from 20 and onwards?
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What are the parts of an integer?

There are 2 parts of integers Positive Integers and Negative Integers. 1:Positive Integers numbers are 1,2,3,4,5,6,7,8,9,................and onwards. 2:Negative Integers numbers are -1,-2,-3,-4,-5.........................and onwards.


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For moderately large numbers, N, you can try dividing by prime numbers up to the square root of N. Each time you find a factor, f, you replace N by N/f, and continue with primes from f onwards. However, this method is impractical for really large numbers: ones that are the product of two primes, each a hundred digits long, for example. And that is why such numbers are used for encryption (codes).


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Why is 3 5 and 7 the only three consecutive odd prime numbers?

All even numbers greater than 2 are composite because they are all divisible by 2. Therefore, from 3 onwards, all prime numbers are odd. Consider three consecutive odd numbers. They must be of the form 2n+1, 2n+3 and 2n+5 where n is an integer. Since n is an integer, n will leave a remainder of 0, 1 or 2 when it is divided by 3. Suppose n leaves a remainder of 0 when divided by 3. Therefore n = 3k for some integer k. Then 2n+3 = 2*(3k) + 3 = 6k + 3 = 3*(2k+1). That is, middle of the three consecutive odd numbers is divisible by 3 and so it is not a prime. Now, suppose n leaves a remainder of 1 when divided by 3. Therefore n = 3k+1 for some integer k. Then 2n+1 = 2*(3k+1) + 1 = 6k+2+1 = 6k+3 = 3*(2k+1). That is, first of the three consecutive odd numbers is divisible by 3 and so it is not a prime. Finally, suppose n leaves a remainder of 2 when divided by 3. Therefore n = 3k+2 for some integer k. Then 2n+5 = 2*(3k+2) + 5 = 6k+4+5 = 6k+9 = 3*(2k+3). That is, last of the three consecutive odd numbers is divisible by 3 and so it is not a prime. Thus for any three consecutive odd numbers greater than 3, one of them is divisible by 3 and therefore the three cannot all be prime.


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As an adverb .


How many times can 1 be subtract from 100?

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