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What is the square root 3 plus square root 6 over square root 2?
Lilbirde
Because questions can't use punctuation the question is ambiguous. Two possible interpretations of the question, with answers are given below:
sqrt(3) + sqrt(6) / sqrt(2) = sqrt(3) + sqrt(6/2) = sqrt(3) + sqrt(3) = 2*sqrt(3)
The more likely question is:
[sqrt(3) + sqrt(6)]/sqrt(2)
Multiply numberator and denominator by sqrt(2) to give
[sqrt(2)*sqrt(3) + sqrt(2)*sqrt(6)]/[sqrt(2)*sqrt(2)]
=[sqrt(2)*sqrt(3) + 2*sqrt(3)]/2 since sqrt(2)*sqrt(2) = 2
= sqrt(3)*[sqrt(2)+1]/2
AnswerSquare root three plus square root six is square root 9 over square root two. But nine can be factored out to a perfect three so you would have 3 over square root two.Wiki User
∙ 14y ago
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