Work it out yourself, apparent power = supply voltage x load current. This, of course, will give you the apparent power in volt amperes, not kilovolt amperes -so you will need to divide your answer by 1000 if you really do need your answer in kilovolt amperes! And the symbol for kilovolt amperes is 'kV.A', not 'kva'.
It depends entirely on the power factor of the load. If the power factor is unity (1), then the true power, in watts, will equal the apparent power in volt amperes. If the power factor is zero, then the true power, in watts, will be zero. This is because true power (watts) is equal to the apparent power (volt amperes) multiplied by the power factor.
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
Pwer is volts times amperes. 120 volts times 10 amperes = 1.2 KW
The current's power factor is the true power divided by the apparent power. The Apparent Power is the volts multiplied by the amps. In this example, the ratio would be 200/253, or approximately .79.
Neither amperes nor volts is the same as watts (power), so the question "what is the higher power" does not make sense.Amperes is electrical current flow, in coulombs per second.Volts is electrical potential, in joules per coulomb.Watts is electrical power, in joules per second, which is also amperes times volts.
40 VA is the apparent power of the load. It is simply the applied voltage multiplied by the resulting current in amperes. Given the VA and the Volts merely divide the VA by the volts to get I=VA/A = 40VA/24V= 1.667 Amperes rms. Andy B
Use the formula: power = current x voltage. In SI units: watts = amperes x volts.
It depends on how many amperes there are. If you have 1 amperes, then you get 260 watts. If you have 260 amperes, then you have 67,600 watts. If you have 0.001 amperes, then you have 0.26 watts. Its just watts = volts times amperes. Of course, the limiting factor is the available power behind the 260 volts, but you did not say anything about that.
Power in watts is voltage in volts times current in amperes.
It depends on how many volts there are. Watts = amperes times volts. If there were 120 volts, there would be 1 ampere. If there were 240 volts, there would be 0.5 amperes. If there were 12 volts, there would be 10 amperes.
(volts x amps)/1000AnswerThe 'volt ampere' (V.A) is the unit of measurement for apparent power of a load, and is the product of the supply voltage and the load current. To convert volt amperes into kilovolt amperes, divide by 1000.
Volts time amperes is watts. Volts is joules per coulomb. Amperes is coulombs per second. When you multiply the two, you get joules per second, which is also known as watts.
A transformer converts voltage to different values (the amount of power remains the same). If you have a transformer with a turns ratio of 1 to 10, and apply 120 volts to the "10" ratio side, you will get 12 volts on the "1" side. If the current on the "10" side is 1 Ampere, the current on the "1" side will be 10 Amperes. Power is equivalent to the voltage times the current, so the power going in the "10" side is (120 volts x 1 ampere = ) 120 watts. The power going out the "1" side is (12 volts x 10 amperes = ) 120 watts as well.
The relationship between amperes, volts, and watts is... watts = amperes * volts Confirming by looking at the fundamental units involved... watts (joules per second) = amperes (coulombs per second) * volts (joules per coulomb)
In a.c. circuits, the product of voltage and current is called 'apparent power', and is expressed in volt amperes. If you want to know the 'true power' of a load, you must multiply its apparent power by the power factor of the load. This is the cosine of the angle by which the load current is (in this case) lagging the supply voltage. Fluorescent lamps have a relatively-low power factor, so the numerical value of the lamp's true power (in watts) will always be somewhat lower than its apparent power (in volt amperes).
Volt Amps [volts times amps] is used for reactive and apparent power. Watts (dimensionally the same as volt amps) is used to indicate real power.AnswerReactive power is measured in reactive volt amperes (var).
Power = volts x amperes x power factor. However, VA or kVA is simply the product of volts x amperes, and does not take into account the power factor. Note that in many practical situations, the power factor is close to 1.
KILOVOLT-AMPERES (kVA) = VOLTS x AMPERES 1000
kva (Killovolt-amperes) is the product of volts and amperes. There for there is no answer to this question since the units are not the same. Example: 1000 volts x 1 amperes = 1000va = 1kva. Also 500 volts x 2 amperes = 1000va = 1kva.
Power (in watts) = Volts * Amps Therefore: 3 Amps * 24 Volts = 72 watts
For a single-phase transformer, divide the ratedapparent power (expressed in volt amperes) by the voltage rating (expressed in volts) of the primary winding; this will give you the rated primary current (expressed in amperes) of the primary winding.
A circuit with a voltage of 240 volts and an inductive reactance of 30 ohms would have a current of 8 amperes.Reactance works just like resistance. The difference is that the phase angle between voltage and current is not zero, so the ratio of true power versus apparent power is not one.Phase angle and power factor depend on frequency. This was not specified in the question, so it is not answered.
Power (watts) = current (amperes) * voltage (volts) Current (amperes) = voltage (volts)/resistance (ohms) 120 watts = current * 120 volts current = 1 ampere 1 ampere = 120 volts/resistance resistance = 120 ohms
Single phase PF = Input Watts/Volts x Amps. Three phase PF =Input Watts/Volts x Amps x1.732.Additional AnswerYou can determine the power factor of a circuit using three instruments: a voltmeter, and ammeter, and a wattmeter.Multiplying the voltmeter reading by the ammeter reading will supply the value of the apparent power in volt amperes. The wattmeter reading will supply the value of the true power in watts.Divide the number of watts by the number of volt amperes, and that will indicate the power factor of the circuit.