US Coins

# What is the value in cents of n nickels?

###### Wiki User

###### October 16, 2015 6:37PM

A nickel is worth 5 cents so n nickels have a value of 5n cents.

## Related Questions

###### Asked in Math and Arithmetic

### You have 7.68 with equal amounts of dimes nickels and pennies. How many dimes do you have?

If you let N represent how many of each coin you have, their
values are:
N pennies = N cents
N nickels = 5N cents
N dimes = 10N cents
so the total value is N + 5N + 10N = 16N cents. That must be equal
to $7.68, or 768 cents, so the final equation is
16N = 768
Solving for N gives you 768/16, or 48 of each coin.

###### Asked in US Coins

### Value of 1956 silver nickels?

###### Asked in US Coins

### How much is 19 nickels?

###### Asked in Math and Arithmetic

### 10 coins consistinig of nickels and dimes equal 80 cents how many coins does she have?

You could (a) use trial and error; (b) write two equations; or
(c) call the number of nickels "n", and the number of dimes "10-n"
(since there are 10 coins in total). I will use the latter
approach.
Number of nickels: n
Number of dimes: 10-n
For the main equation, multiply the number of coins by the value
of each coin:
value of nickels + value of dimes = 80
5n + 10(10-n) = 80
Now solve the equation:
5n + 100 - 10n = 80
-5n = -20
5n = 20
n = 4
So, you have 4 nickels, and 6 dimes.
You could (a) use trial and error; (b) write two equations; or (c)
call the number of nickels "n", and the number of dimes "10-n"
(since there are 10 coins in total). I will use the latter
approach.
Number of nickels: n
Number of dimes: 10-n
For the main equation, multiply the number of coins by the value
of each coin:
value of nickels + value of dimes = 80
5n + 10(10-n) = 80
Now solve the equation:
5n + 100 - 10n = 80
-5n = -20
5n = 20
n = 4
So, you have 4 nickels, and 6 dimes.
You could (a) use trial and error; (b) write two equations; or (c)
call the number of nickels "n", and the number of dimes "10-n"
(since there are 10 coins in total). I will use the latter
approach.
Number of nickels: n
Number of dimes: 10-n
For the main equation, multiply the number of coins by the value
of each coin:
value of nickels + value of dimes = 80
5n + 10(10-n) = 80
Now solve the equation:
5n + 100 - 10n = 80
-5n = -20
5n = 20
n = 4
So, you have 4 nickels, and 6 dimes.
You could (a) use trial and error; (b) write two equations; or (c)
call the number of nickels "n", and the number of dimes "10-n"
(since there are 10 coins in total). I will use the latter
approach.
Number of nickels: n
Number of dimes: 10-n
For the main equation, multiply the number of coins by the value
of each coin:
value of nickels + value of dimes = 80
5n + 10(10-n) = 80
Now solve the equation:
5n + 100 - 10n = 80
-5n = -20
5n = 20
n = 4
So, you have 4 nickels, and 6 dimes.