Ignoring the effects of air resistance, the velocity of any object dropped
near the surface of the Earth is 29.42 meters (96.53 feet) per second,
directed downward, after it has fallen 3 meters.
If you're working with situations and asking questions like this one, then
you're supposed to know by now that the mass or weight of the object
makes no difference. If you can eliminate air resistance, then the answer
is the same for a feather, a Bowling ball, and a battleship.
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
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If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
Here are two different methods to solve this kind of problem. 1) Use one of the formulae for constant acceleration. In this case, vf2 = vi2 + 2as, where vf is the final velocity, vi is the initial velocity (zero in this case), a is the acceleration (9.8 meters / second2), and s is the distance. 2) Do an energy calculation, as follows: Calculate the potential energy at a height of 6 meters, with the formula PE = mgh. Since we can assume that the entire potential energy gets converted to kinetic energy just before the ball hits the ground, solve for velocity, in the kinetic energy formula.
The building is h=.5 gt^2 meters tall; that is = .5x9.8 x25 =122.5 meters.
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
176.4 meters
No because you touch yourself at night.|_ 4 VV |_Just kidding. It does!Psyche!Actually, it does not because when your mother dropped you from 2 meters above the ground, you fell at a negative VELOCITY. Speed does not specify direction, and therefore can not be negative.
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.