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If we apply Ohm's law, which is E = I x R and we have a voltage (E) of 110 volts and a current (I) of 10 amps, we can use the variation of the formula to solve. That variation is R = E / I and the resistance (R) is discovered by dividing the voltage by the current. R = E / I = 110 / 10 = 11 ohms
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∙ 15y ago
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∙ 12y agoOhm's Law: Voltage is current times resistance
10 amperes times 2 ohms equals 20 volts
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∙ 12y agoOhm's Law: Current is voltage divided by resistance, so 10 volts divided by 2 ohms is 5 amperes.
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∙ 10y agoAs V=IR, thus I=V/R.
So substituting the values into the equation: I=10V/2Ω=5A
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∙ 9y agoThe voltage in a circuit that has a current of 10.0 amps and a resistance of 28 ohms is 285 V. Those 285 volts are equal to 10 A (amperes) and 0.285 kV (kilovolts).
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∙ 11y agoThe formula you are looking for is E = I x R. Volts = Amps x Resistance.
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∙ 6y agoUnder a Direct Current and pure resistive circuit condition, you need 50 Volts. V = IR, where V is voltage, R is restance, I is current.
John Mark Pagalpalan
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Nathaniel Williams
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What is the affect of a series circuit on current?
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
How is total resistance in a series circuit determined?
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?
Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.The divider will be composed of 4 resistors starting at the 10VDC rail:2VDC drop, ratio = 2V/10V = 0.23VDC drop, ratio = 3V/10V = 0.33VDC drop, ratio = 3V/10V = 0.32VDC drop, ratio = 2V/10V = 0.2Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.But as stated at the beginning you can get no further without additional requirements being specified.
How will a current change if the resistance of a circuit remain constant while the voltage across the circuit decreases to half its original value?
Voltage = resistance X current abbreviated,V = C * RIf you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:(1/2)V=(1/2)(C*R)which is the same as:(1/2)V=(1/2)(C)(R)which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.
What is the affect of a series circuit on current?
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
What is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts?
Use the formula: P=IR (power = current x resistance).
In series circuit is currant change with change in resistance?
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
Why is there no flow of electric current?
There are two possible causes: 1. The circuit has no Voltage applied to it. 2. The resistance of the circuit is INFINITE.
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
How is total resistance in a series circuit determined?
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
What is the power of a ciruit with 10 ohmns 10 volts and 2 amps?
Well, first of all, if the resistance of the circuit is 10 ohms and you connect 10 volts to it,then the current is 1 Amp, not 2 . So either there's something else in your circuit thatyou're not telling us about, or else the circuit simply doesn't exist.-- If you connect some voltage to some resistance, then the resistance heats up anddissipates (voltage)2/resistancewatts of power, and the power supply has to supply it.-- If there is some current flowing through some resistance, then the resistance heats up anddissipates (current)2 x (resistance)watts of power, and the power supply has to supply it.-- If there's a circuit with some voltage connected to it and some current flowingthrough it, then the resistance of the circuit is (voltage)/(current) ohms, the partsin the circuit heat up and dissipate (voltage) x (current) watts of power, andthe power supply has to supply it.There's no such thing as "the power of a circuit". The power supply supplies thecircuit with some amount of power, the circuit either dissipates or radiates someamount of power, and the two amounts are equal.
Is electric circuit also called series circuit?
The 2 simplest Electrical circuits areSeries Circuit - Same amount of current running through loads but voltage various by the resistance of the loadsParallel Circuit - Same voltage on the different loads by subject to the load resistance, the current passing through is different
How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?
Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.The divider will be composed of 4 resistors starting at the 10VDC rail:2VDC drop, ratio = 2V/10V = 0.23VDC drop, ratio = 3V/10V = 0.33VDC drop, ratio = 3V/10V = 0.32VDC drop, ratio = 2V/10V = 0.2Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.But as stated at the beginning you can get no further without additional requirements being specified.
In a circuit with a 6 V battery hooked up to a 3 Ohm light bulb what does the current measure?
2 amperes (current = voltage/resistance)
How will a current change if the resistance of a circuit remain constant while the voltage across the circuit decreases to half its original value?
Voltage = resistance X current abbreviated,V = C * RIf you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:(1/2)V=(1/2)(C*R)which is the same as:(1/2)V=(1/2)(C)(R)which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.
How does resistance affect the current in a circuit?
Resistors are used for many things in an electronic circuit, including creating a voltage drop at some point; attenuating noise on a signal before it reaches the output stage; in combination with transistor devices, split a signal into 2 opposite phases; present a minimum load to a device to keep it working at its optimum point; to create an appropriate bias level for transistor device inputs; to control a timing circuit in conjunction with a capacitor; to create a tuned circuit in conjunction with an inductor, and/or a capacitor . . . . and the list goes on . . .
