0
What is the volume and surface area of a sphere when its circumference is 23.565 inches taking pi as 3.142?
Wiki User
∙ 12y ago
Radius = 23.565/(2*3.142) = 3.75 inches
Volume = 4/3*3.142*3.753 = 220.921875 cubic inches
Surface area = 4*3.142*3.752 = 176.7375 square inches
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
What is the radius and circumference of a sphere when its surface area covers 314 square inches taking pi as 3.14 and showing your work?
S.A. = 4 pi r^2 Substituting 314 = 43.14r^2 Algebraically rearrange 100/4] r^2 = 314 / (4 * 3.14) r = sqrt[314/(4*3.14)] r = sqrt[ 100/4] r = sqrt[25] r = 5 inches The circumference of a sphere is a circle. Hence C = 2 pi r C = 23.145 C = 10*3.14 C = 31.4 inches.
What is the surface area of a size 5 soccer ball?
The circumference of a Size five soccer ball is 27-28 inches according to the rules of soccer. (FIFA RULE BOOK)Now if C= the circumference, we know that C=2Pi(r), where r is the radius and Pi is the constant Pi which we approximate with 3.14. You may use 22/7 if you prefer.(If you want a better approximation, consider using Pi = 3.14159265, however, it does not make sense to use Pi to 4 or 5 significant digits if the measurement of the circumference is not even close to that accurate. That is why we did not do so here.)The surface area of a sphere is 4Pir2 . A soccer ball is NOT a sphere, but this is a good approximation. (In reality it is a truncated icosahedron which is made up of regular pentagons and regular hexagons. Once you add the air to the ball, it becomes close enough to a sphere to use a spherical model as an excellent approximation. Once could easily calculate the area of 1 of the hexagons and 1 of the pentagons and find the surface area exactly. It might be fun to do so and compare to the answer using the sphere!)So first we find that ( C2 /4Pi2 )=r2This come from taking C=2Pi(r) which is the definition of circumference of a sphere and dividing both sides by 2xPi givingC/2Pi =r, then square both sides and you have ( C2 /4Pi2 )=r2 . Now substitute that into the formula for surface area.SA= 4Pir2 =4Pi( C2 /4Pi2 ).Now note that the 4 cancel as does one of the Pi'sso we haveSA=C2 /Pi=272 /3.14 approximately 232.2 square inches. This is about 1.6 square feet.Now if we use C=28 we have about 249.682 square inches which is 1.7 square feet.So the answer is between 1.6 and 1.7 square feet.Method 2We can also start with circumference C=27- 28 inches.and C=2Pi(r) as mentioned above.So r=14/Pi or about 4.456 inches. This is the radius of the soccer ball.Now Surface area is 4XPiXr2 = 4xPix4.4562this is 249.55 square inches.Using 27 instead of 28 we have r=4.29718and Surface area is 4xPix4.297182 =232.048 square inches.When we convert 249.55 to square feet by dividing by 144 square inches per square foot, we get 1.7 square feet ( 1.73299) and for 232.048 we get 1.6 (1.61144). So the answer is the same. There are some rounding errors and the problem can be redone to any degree of accuracy needed.The advantage of Method 1 is that you find a formula for the SA, the surface area by using the circumference. This method will allow you to plug in the circumference for a size 4 ball, for example and find its area right away. Method 2 requires you to find the radius give the circumference. This works well too, but you need to find r each time C changes.
Calculating square inches of a circle?
The area of a circle is easily found by multiplying its radius squared times the constant pi. If only the circumference is known, the radius is found by taking 1/2 of the circumference divided by pi.
What is the easiest net for a sphere?
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.
What is the ratio of surface area to volume for a sphere with the following measurements surface area equals 588 M squared volume equals 1372 m to the Third?
The formula for the surface area of a sphere is 4πr² and the formula for the volume is (4/3)πr³, where r is the radius of the sphere. Setting 4πr² equal to 588 and (4/3)πr³ equal to 1372, you can solve for the radius by equating the two expressions and taking the cube root of the result. Once you have the radius, you can calculate the surface area using the formula and divide it by the volume to find the ratio.
What is the radius and circumference of a sphere when its surface area covers 314 square inches taking pi as 3.14 and showing your work?
S.A. = 4 pi r^2 Substituting 314 = 43.14r^2 Algebraically rearrange 100/4] r^2 = 314 / (4 * 3.14) r = sqrt[314/(4*3.14)] r = sqrt[ 100/4] r = sqrt[25] r = 5 inches The circumference of a sphere is a circle. Hence C = 2 pi r C = 23.145 C = 10*3.14 C = 31.4 inches.
What is 100 times bigger than a basketball?
A basketball which meets the men's NBA standards has a circumference of 29.5". That gives a radius of 4.695 inches, which we can then put into the formula for the volume of a sphere - 4/3Πr3. That works out at 1.3333 x 3.1416 x 103.4920 = 433.4964619 cubic inches. A volume 100 times greater than that would be 43349.64619 cubic inches and taking that down to a radius by reversing the formula above, we get 3√ 43349.64619 ÷ 1.3333 ÷ 3.1416 = 21.7923 So, a sphere which is 43.5846 inches in diameter (that's just over 3 foot 7 inches across) would be 100 times the volume of a men's regulation basketball.
Why are map projections not true representations of the earth's surface?
This is due to the distortions caused by taking a 3 dimensional sphere and converting it to a 2 dimensional layout.
What is the surface area of a size 5 soccer ball?
The circumference of a Size five soccer ball is 27-28 inches according to the rules of soccer. (FIFA RULE BOOK)Now if C= the circumference, we know that C=2Pi(r), where r is the radius and Pi is the constant Pi which we approximate with 3.14. You may use 22/7 if you prefer.(If you want a better approximation, consider using Pi = 3.14159265, however, it does not make sense to use Pi to 4 or 5 significant digits if the measurement of the circumference is not even close to that accurate. That is why we did not do so here.)The surface area of a sphere is 4Pir2 . A soccer ball is NOT a sphere, but this is a good approximation. (In reality it is a truncated icosahedron which is made up of regular pentagons and regular hexagons. Once you add the air to the ball, it becomes close enough to a sphere to use a spherical model as an excellent approximation. Once could easily calculate the area of 1 of the hexagons and 1 of the pentagons and find the surface area exactly. It might be fun to do so and compare to the answer using the sphere!)So first we find that ( C2 /4Pi2 )=r2This come from taking C=2Pi(r) which is the definition of circumference of a sphere and dividing both sides by 2xPi givingC/2Pi =r, then square both sides and you have ( C2 /4Pi2 )=r2 . Now substitute that into the formula for surface area.SA= 4Pir2 =4Pi( C2 /4Pi2 ).Now note that the 4 cancel as does one of the Pi'sso we haveSA=C2 /Pi=272 /3.14 approximately 232.2 square inches. This is about 1.6 square feet.Now if we use C=28 we have about 249.682 square inches which is 1.7 square feet.So the answer is between 1.6 and 1.7 square feet.Method 2We can also start with circumference C=27- 28 inches.and C=2Pi(r) as mentioned above.So r=14/Pi or about 4.456 inches. This is the radius of the soccer ball.Now Surface area is 4XPiXr2 = 4xPix4.4562this is 249.55 square inches.Using 27 instead of 28 we have r=4.29718and Surface area is 4xPix4.297182 =232.048 square inches.When we convert 249.55 to square feet by dividing by 144 square inches per square foot, we get 1.7 square feet ( 1.73299) and for 232.048 we get 1.6 (1.61144). So the answer is the same. There are some rounding errors and the problem can be redone to any degree of accuracy needed.The advantage of Method 1 is that you find a formula for the SA, the surface area by using the circumference. This method will allow you to plug in the circumference for a size 4 ball, for example and find its area right away. Method 2 requires you to find the radius give the circumference. This works well too, but you need to find r each time C changes.
Calculating square inches of a circle?
The area of a circle is easily found by multiplying its radius squared times the constant pi. If only the circumference is known, the radius is found by taking 1/2 of the circumference divided by pi.
Would a curved universe require a centipetal force to keep galaxies on its nonrectilinear surface?
No. You obviously misuderstand the concept of a "curved" universe, probably imagining it like the 2-D surface on a 3-D sphere. This actually isn't too bad of a way to view it, but it has its problems -- caused mainly by taking the mathematical analogy too far. A Friedmann Universe -- ie, one like the one we're now in -- can be mathematically curved but without a surface, and without any other dimension into which this curvature is (well) curving. Even in a universe that was 2-D and closed (ie, a sphere), and its mass was constrained to the surface of a sphere, then no force would be needed to keep that mass on the surface. That mass could no more leave the surface of the sphere then you could walk outside of the three spatial dimensions of our Universe.
Are there any isolated tiny time zones?
Since there are a total of 24 time zones, then taking the Earth as a perfect sphere of 360o's, then each time zone covers 15o's of the Earth's surface.
What is the easiest net for a sphere?
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.
What is the ratio of surface area to volume for a sphere with the following measurements surface area equals 588 M squared volume equals 1372 m to the Third?
The formula for the surface area of a sphere is 4πr² and the formula for the volume is (4/3)πr³, where r is the radius of the sphere. Setting 4πr² equal to 588 and (4/3)πr³ equal to 1372, you can solve for the radius by equating the two expressions and taking the cube root of the result. Once you have the radius, you can calculate the surface area using the formula and divide it by the volume to find the ratio.
What is the circumference of a circle with a diameter of 32cm taking pi as 3.14?
circumference = π × diameter = 3.14 × 32 cm = 100.48 cm
If L equals 6 inches W equals 4 inches and H equals 3 inches what is the surface area of the rectangular prism?
Taking the four sides as each having 6 inch length, and the sum of the widths and heights of the sides being 14 inches, the area of the sides is 84 square inches (6 x 14), and the area of the ends is 24 square inches (2 x 3 x 4), for a total surface area of 108 square inches.
What is the total surface area of a hemispherical shape with a circumference of 43.988 cm taking pi as 3.142?
Remember to include the flat surface of the hemisphere in your answer and halve the fomula of 4*pi*radius squared: Radius = 43.988/(2*3.142) = 7 cm Total surface area = (3.142*72) + (2*3.142*72) = 461.874 square cm
