volume_cuboid = length × width × height = 4 ft × 2.3 ft × 5 ft = 46 cu ft
surface_area_cuboid = 2 × (length × width + width × height + height × length)
= 2 × (4 ft × 2.3 ft + 2.3 ft × 5 ft + 5 ft × 4 ft)
= 2 × (9.2 sq ft + 11.5 sq ft + 20 sq ft)
= 2 × 40.7 sq ft
= 81.4 sq ft
The surface area of a sphere with a diameter of 2.7 inches is about 23 square inches.
Find the surface area of a cylinder with a radius of 16 and a height of 23. Use 3.14 for π. Round your answer to the nearest te
The volume of a sphere is proportional to R3 .So doubling the radius causes the volume to increase by a factor of 23 = 8 .
The area is 1,661.9 square yards.
2,821.09 cu ft
The new area is 22 = 4 times the original area. The new volume is 23 = 8 times the original volume.
A "cute" cube with sides of 2mm has a volume of 23 cu.mm. = 8 cubic mm. The surface area is 2*2 each, times 6 surfaces = 24 square mm. Surface area to volume ratio is 24:8 which is 3:1 By the way, the ratio is 1:1 when the sides are 6mm (or 6cm or 6m or 6km).
The surface area of a sphere with a diameter of 2.7 inches is about 23 square inches.
Entire surface area: (2*pi*121)+(22*pi*23) = = 748*pi square inches
Volume of prism = Base area x height = 54 square metres x 23 metres = 1242 cubic metres.
The surface area of a cube with edge 23±0.0004 cm is 3174±0.11 cm.The surface area is edge squared times 6. The surface area at 23.0004 is 3174.1104. The surface area at 22.9996 is 2173.8896.
Because volume is a cubic function of the size of the cell, and surface area is a square function of the same size, it is logical that the volume would increase more rapidly, but let's prove it to ourselves with the math. ---------------------------------------------------------------------- Let's assume the cell is spherical (just for example): Formula for the surface area of a sphere: A = 4 pi r2 Formula for the volume of a sphere: V = 4/3 pi r3 Let's also assume that the cell has a radius of 1 unit to start: A = 4 pi 12 = 12.56 sq units V = 4/3 pi 13 = 4.19 cu units So let's imagine the radius increases to 2 units. How would that affect the surface area and volume? A2 = 4 pi 22 = 50.24 sq units (a 300% increase in surface area) V2 = 4/3 pi 23 = 33.49 cu units (a 700% increase in volume) Ok, now let's grow the cell to a radius of 3 units... A3 = 4 pi 32 = 113 sq units (a 125% increase from the last time) V3 = 4/3 pi 33 = 113.04 cu units (a 235% increase from last time) For any increase in the radius of a spherical cell, the increase in volume is always greater than the increase in the surface area. Also notice that, as the cell increases in size, the ratio of the surface area to the volume decreases - smaller objects have a greater surface area/volume ratio than larger ones. But that's another post...
Find the surface area of a cylinder with a radius of 16 and a height of 23. Use 3.14 for π. Round your answer to the nearest te
volume 23 comes out in June 3rd volume 23 comes out in June 3rd
It is: 4*pi*11.5squared = 529*pi square feet
First find the radius by dividing 23 by 2*pi which works out as 3.660563691 Surface area of the sphere = 4*pi*3.6605636912 = 168.3859298 or about 168 square mm
Yes, and everything that happens in it is real. there are 23 volumes out. volume 23 is the final volume